Answer:
second lag
Explanation:
If in a cup game, a specified time limit is assigned to both teams to score high. If both teams are unable to score or if score of both the teams is equal then there is another second lag played where each team tries to score high. Even if in second lag both teams fail to score higher than other the last third lag is played or else game is declared draw.
Answer: R = 0.131 m
Explanation: The formulae for the distance between a fringe and the first (center) is given by
y = R×mλ/d
Where y = distance between first and nth fringe = 4mm = 4×10^-3m
λ = wavelength of light = 441.1nm = 441.1×10^-9m
R = distance between slits and screen =?
d = distance between slits = 0.29mm = 2.9×10^-4m
4×10^-3 = R ×2 ×441.4×10^-9/ 2.9×10^-5
Hence R = (4×10^-3) ×(2.9×10^-5)/2×441.4×10^-9
R = 1.16 × 10^-7/8.828×10^-7
R = 1.16/8.828
R = 0.131 m
Answer:
Explanation:
From the Question we are told that
Mass of A and B is 60kg
Speed of A=2m/s
Speed of B=1m/s
Mass of bag =5kg
Generally the momentum of the astronaut A and bag is mathematically given as
Generally to avoid collision the speed of astronaut be should be less than or equal to that of astronaut A with the bag
Therefore for minimum requirement speed of astronaut A should be given by astronaut B's speed which is equal to 1
Therefore
Answer: The first crane has greater power
Explanation:
