B. opposite charge and smaller mass
Answer:
The current is 0.248 A
Explanation:
Given that,
Inductor 
Resistance 
Voltage = 15 volt
Time 
We need to calculate the current
Using formula of current

Where, V = voltage
R = resistance
L = inductance
T = time
Put the value into the formula


Hence, The current is 0.248 A.
Genus’s mastermind hope that helps
Answer:
Speed of wind = 50mi/hr, Speed of plane in still air = 400mi/hr
Explanation:
Let the speed of the wind = Vw,
Speed of the plane in still air = Vsa,
The first trip the average speed of the plane = 1575mi/4.5hours = 350mi/hr
The coming trip the wind behind = 1575mi/3.5hrs = 450
Write the motion in equation form
First trip ( the plane flew into the wind)
Vaverage = Vsa - Vw
350 = Vsa - Vw
Second trip the wind was behind
450 = Vsa +Vw
Adding the two equation
800 = 2Vas
Vas = 800/2 = 400mi/hr
Substitute for Vas into equation 1
350mi/hr = 400mi/hr - Vw
Vw = 400-350 = 50mi/hr