M1 v1 = (m1 + m2)v2.
All of the exponents should be lowered to the bottom right of the letters.
Answer:
Explanation:
Yes , their displacement may be equal .
Suppose the displacement is AB where A is starting point and B is end point .
The car is covering the distance AB by going from A to B on straight line . On the other hand plane goes from A to C , then from C to D and then from D to B . In this way plane reaches B from A on a different path which is longer than path of the car . In the second case also displacement of plane is AB . In the second case distance covered is longer but displacement is same that is AB .
Let's apply an equation of equilibrium to the situation: The sum of the moments about the left end of the board must equal 0.
We have three moments to add. Positive force values indicate upward direction and negative values indicate downward direction. All distances given below are measured to the right side of the left end of the board:
- The weight of the board, -125N, located at 2m (center of the board due to its uniform density)
- The tension in the right chain, +250N, located at 4m
- The weight of the person, -500N, located at a distance "x"
The sum of the moments must equal 0 and is given by:
ΣFx = 0
F is the magnitude of force, x = distance from the left end of the board
Plug in all of the force and distance values and solve for x:
ΣFx = 250(4) - 125(2) - 500x = 0
500x = 750
x = 1.5m
So you know the speed of a wave, and speed is how much the wave moves per second. This wave travels 3x10^8 meters per second. So to find how for you traveled you need to know how many seconds the wave traveled for, 20 minutes is equal to 1200 seconds (times 20 minutes by 60). Then times the seconds by the speed (3x10^8 m/s)x(1200 s) = 3.6x10^11 meters
