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3 years ago

13

How do i get a bf and how do i start to talk to him? I have this one crush and we have not even said one word to each other, Hes

in my 1 and 2 per plz tell me

2 answers:

yanalaym [24]3 years ago

8 0

Answer:

I would compliment him and get to know him

Explanation:

taurus [48]3 years ago

4 0

First introduce yourself. Start talking to him little by little. Compliment him, that’ll help. Make some jokes, and talk about stuff he is interested in. Make conversation. Try not to be overbearing.

You might be interested in

An ant crawls in a straight line at a constant speed of 0.24 m/s for a distance of 3.0 m, beginning in the corner of a square cl

Talja [164]

Answer:

vavg = 0.37 m/s

Explanation:

The average speed is just the relationship between the total distance traveled, and the total time required for that travel , as follows:

$v_{avg} = \frac{\Delta x}{\Delta t} (1)$

We know that for the first leg of the journey, the ant crawls at a constant speed of 0.24 m/s, moving 3.0 m.
We can find the time required for this part, just applying the definition of average velocity, and solving for the time t (which we will call t₁), as follows:

$t_{1} =\frac{x_{1}}{v_{1} } = \frac{3.0m}{0.24m/s} = 12.5 s (2)$

From the givens, we know that the time for the second part is exactly the half of the value found in (2), so we can write the total time Δt as follows:

$\Delta t = t_{1} + \frac{t_{1} }{2} = 12.5 s + 6.25 s = 18.75 s (3)$

We also know that in the second leg of the journey, the ant traveled 4.0 m, which adds to the 3.0 m of the first part, making a total distance of 7.0 m.
Per definition of average speed, we can write the following expression as in (1) replacing Δx and Δt by their values, as follows:

$v_{avg} = \frac{\Delta x}{\Delta t} = \frac{7.0m}{18.75m} = 0.37 m/s (4)$

3 0

3 years ago

Optical tweezers use light from a laser to move single atoms and molecules around. Suppose the intensity of light from the tweez

Zanzabum

(a) $3.3\cdot 10^{-6} Pa$

The radiation pressure exerted by an electromagnetic wave on a surface that totally absorbs the radiation is given by

$p=\frac{I}{c}$

where

I is the intensity of the wave

c is the speed of light

In this problem,

$I=1000 W/m^2$

and substituting $c=3\cdot 10^8 m/s$ , we find the radiation pressure

$p=\frac{1000 W/m^2}{3\cdot 10^8 m/s}=3.3\cdot 10^{-6}Pa$

(b) $4.4\cdot 10^{-8} m/s^2$

Since we know the cross-sectional area of the laser beam:

$A=6.65\cdot 10^{-29}m^2$

starting from the radiation pressure found at point (a), we can calculate the force exerted on a tritium atom:

$F=pa=(3.3\cdot 10^{-6}Pa)(6.65\cdot 10^{-29} m^2)=2.2\cdot 10^{-34}N$

And then, since we know the mass of the atom

$m=5.01\cdot 10^{-27}kg$

we can find the acceleration, by using Newton's second law:

$a=\frac{F}{m}=\frac{2.2\cdot 10^{-34} N}{5.01\cdot 10^{-27} kg}=4.4\cdot 10^{-8} m/s^2$

6 0

3 years ago

A stereo speaker is placed between two observers who are 40 m apart, along the line connecting them. if one observer records an

Nadya [2.5K]

The distance from observer A of intensity of sound 59 db is 28.64 m and the distance from observer B of intensity of sound 83 db is 11.36m

Explanation:

Let's solve this problem in parts

let's start by finding the intensity of the sound in each observer

observer A β = 59 db

β = $10 log\frac{I_a}{I_o}$

where I₀ = $1 \times 10^{-12}$ W / m²

$I_a = I_b \times 10 ^{ \frac{\beta}{10} }$

$I_a = 1\times 10 ^{-12} \times 10 ^{ \frac{59}{10} }$

$I_a$ = $2.51 \times 10 ^{-6}$ W / m²

Similarly for Observer b $I_b = 3.16 \times 10 ^ {-4}$

now we use that the emitted power that is constant is the intensity over the area of the sphere where the sound is distributed

P = I A

therefore for the two observers

the area of a sphere is

$A= 4\pi \times r^2$

we substitute the above formula, we get

Let us call the distance from the observer A be to stereo speaker = x, so the distance from the observer B to the stereo speaker = 40- x; we substitute

$I_a (35 -x) ^2 = I_b x^2$

after solving the above equation we get x = 28.64 m

This is the distance of observer A

similarly The distance from observer B is 35 - x

= 40 - 28.64

= 11.36m

To know more about intensity of sound with the given link

#SPJ4

6 0

1 year ago

Imagine you had a bar of gold and decided to cut in half. You repeated this process until eventually you could no longer cut the

nydimaria [60]

This would prove that gold is an <em>element</em>. No matter how far down you
examine it, you never find any particles of anything except gold.

An example of a different case is salt.
-- Imagine you had a block of salt and decided to cut it in half.
-- If you repeated this process, then eventually, at some point, you'd have
a tiny particle of salt in front of you, just like before. BUT ...
-- Just as you were getting ready to cut this one in half, you'd notice that this
particle of salt is different. It's one atom of sodium stuck to one atom of chlorine,
and if you cut it in half, you would not have ANY salt. <span />

This would prove that salt is a <em><u>compound</u></em>, made of atoms of two or more elements.

3 0

4 years ago

Read 2 more answers

A pneumatic system consists of several identical 1.5 inch diameter cylinders to lift 450-pound pallets in a warehouse. the gauge

DerKrebs [107]

The applicable equation:

P = F/A

P = pressure
F = Force or weight
A = surface area

Pressure on each cylinder = (W/n)/A
Where n = number of cylinders. Additionally, pressure in the reservoir is equivalent to the pressure in each cylinder.
Net pressure = 75 - 14.7 = 60.3 psi

Therefore,
60.3 = (W/n)/A = (450/n)/(πD^2/4) = (450/n)/(π*1.5^2/4) = (450/n)/(1.7671)
60.3*1.7671 = 450/n
106.03 = 450/n
n = 450/106.3 = 4.244 ≈ 5

The number of cylinders is 5.

3 0

3 years ago