True or false Scientific conclusions can and should be based on more than just observable evidence.

What is unit? write down the unit of mass temperature power and density

emmainna [20.7K]

Answer:

The SI unit for length is meters(m), for mass is kilograms(kg), for volume is cubic meter(m^3), for density kilogram per cubic meter(kg/m^3), for time is seconds(s), and for temperature is kelvins(K).

Explanation:

hope... the answer was helpful

4 0

3 years ago

The gravitational force between two asteroids is 2.59 × 10 (exponent)-6 N. The centers of mass are 2000 meters away and their ma

makkiz [27]

Answer:

$2.79 \times 10^5 \ \text{kg}$

Explanation:

Newton's Law of Universal Gravitation:

$$F= G\frac{m_1 m_2}{r^2}$
F = force of gravity (N)
G = gravitational constant $(6.67 \times 10^-^1^1 \ N\frac{m^2}{kg^2})$
$m_1$ = mass of Object 1 (kg)
$m_2$ = mass of Object 2 (kg)
r = distance between the center of mass (m)

Let's convert our given information to scientific notation:

$2000 \ m \rightarrow 2.0 \times 10^3 \ m$

Now using the gravitational force and the distance between centers of mass that are given, we can plug these into Newton's law:

$2.59 \times 10^-^6 $\ N = 6.67 \times 10^-^1^1 \ N \frac{m^2}{kg^2} \times \frac{m_1 m_2}{(2.0 \times 10^3 \ m)^2}$

Remove the units for better readability.

$2.59 \times 10^-^6=6.67 \times 10^-^1^1 \frac{m_1m_2}{(2.0 \times 10^3)^2}$

Divide both sides of the equation by the gravitational constant G.

$\frac{2.59 \times 10^-^6}{6.67 \times 10^-^1^1} =\frac{m_1m_2}{(2.0 \times 10^3)^2}$

Distribute the power of 2 inside the parentheses.

$\frac{2.59 \times 10^-^6}{6.67 \times 10^-^1^1} =\frac{m_1m_2}{2.0 \times 10^6}$

If we evaluate the left side of the equation, we get:

$3.88305847 \times 10^4 = \frac{m_1m_2}{2.0 \times 10^6}$

Multiply both sides of the equation by r.

$7.76611694 \times 10^1^0= m_1m_2$

In order to find the mass of one asteroid, we can use the fact that both asteroids have the same mass, therefore, we can rewrite $m_1m_2$ as $m^2$ .

$7.76611694 \times 10^1^0= m^2$

Square root both sides of the equation.

$m=\sqrt{7.76611694 \times 10^1^0}$

$m=2.78677536 \times 10^5$
$m=2.79 \times 10^5$

Since m is in units of kg, we can state that the mass of each asteroid is 2.79 * 10⁵ kg.

3 0

3 years ago

Help!!

Roman55 [17]

D. Circulatory
The digestive system works very closely with the circulatory system to get the absorbed nutrients distributed through your body. The circulatory system also carries chemical signals from your endocrine system that control the speed of digestion.

5 0

3 years ago

Why is it important to set a series of short-term goals?

olchik [2.2K]

Answer:

It ultimately helps you focus on your long-term goals

Explanation:

6 0

3 years ago

Read 2 more answers

How much time is required for reflected sunlight to travel from the Moon to Earth if the distance between Earth and the Moon is

mafiozo [28]

1.3 second of time will be required for reflected sunlight to travel from the Moon to Earth if the distance between Earth and the Moon is 3.85 × 105 km

<h3>What is Speed ?</h3>

Speed is the distance travelled per time taken. It is a scalar quantity. And the S.I unit is meter per second. That is, m/s

In the given question, we want to find how much time is required for reflected sunlight to travel from the Moon to Earth if the distance between Earth and the Moon is 3.85 × 10^5 km.

What are the parameters to consider ?

The parameters are;

The distance S = 3.85 × $10^{5}$ km

The Speed of Light C = 3 × $10^{8}$ m/s

The time taken t = ?

Speed = distance S ÷ Time t

Convert kilometer to meter by multiplying it by 1000

C = S/t

3 × $10^{8}$ = 3.85 × $10^{8}$ / t

Make t the subject of formula

t = 3.85 × $10^{8}$ / 3 × $10^{8}$

t = 1.2833

t = 1.3 s

Therefore, 1.3 second of time will be required for reflected sunlight to travel from the Moon to Earth if the distance between Earth and the Moon is 3.85 × 105 km

Learn more about Speed here: brainly.com/question/4931057

#SPJ1

3 0

2 years ago