Explanation:
Noble gases are group O elements and their atomic structure ensures that they are stable. All their orbitals are completely filled with electrons therefore they do not undergo reactions with other elements.
- Heavier noble gases are able to form a range of compounds due their sizes.
- Elements form compounds by exchanging or sharing of their outermost shell electrons called the valence electron.
- Every atom has specific energy required to remove electrons from them. The energy is known as the ionization energy.
- In bigger atoms which have large radius, the outermost electrons have low ionization energy which makes them easy to remove.
- The ionization energy depends on the nuclear charge, the more the charge the higher the ionization energy. Down a group the nuclear charge and ionization decreases.
- As we go down the inert group, the ionization energy of outer shell electrons become very low. This makes the electrons available to take part in chemical reactions.
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Answer:
Reflection takes place from the polished smooth surfaces
Explanation:
A vacuum does not refer to an opaque body. An opaque body does not allow light to pass through it while a vacuum is simply empty space without air.
A smooth polished surface often acts as a mirror, it is a good reflector of light.
The moon is a non luminous body in the sky. It merely reflects the light from the sun.
A Pinhole camera can not take pictures of moving objects because it only focuses on any image placed before it.
Shadows are not inverted, the always appear upright.
POH+pH=14
pH=14-pOH=14-3.53=10.47
pH=-log[H⁺]
[H⁺]=10^(-pH)
[H⁺]=10^(-10.47)=3.4*10(^-11)
The problem in this question can be solved using the ideal gas formula. Ideal gas formula show interaction between the pressure, volume, temperature and the number of molecules.
n= number of molecule/ avogadro number
n= (2.0116 x 10^23 / 6.02*10^23)= 1/3 mole
T= celcius + 273.15
T= (41+273.15) K=314.15
P=2280 mmHg / (760mmHg/atm)= 3 atm
PV=nRT
V= nrT/ P
V= 1/3 moles * (<span>0.08205 L atm / mol·K) </span> * 314.15 K / 3 atm
V= 2.864 L
