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elena-14-01-66 [18.8K]
4 years ago
9

Please answer each thank you

Chemistry
1 answer:
liubo4ka [24]4 years ago
3 0

Answer:

Properties of Metals:      

- Shiny

-Malleable

-Good Conductors of electric current

- Good conductors of heat

Properties of Non-metals:

- Dull

- Not Malleable

- Bad conductors of electric current but good electric insulators

- Poor conductors of heat

Note: The first dash for the Properties of metals goes with the first dash of Properties of Non-metals and so on.

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12) A 17.92 g sample of copper was submerged in water, and the volume reading rose by 2.00 mL. What is the density of the copper
emmasim [6.3K]

Hey there!:

Mass = 17.92 g

Volume = 2.00 mL

Density =  ??

Therefore:

D = m / V

D = 17.92 / 2.00

D = 8.96 g/mL

Hope this helps!

3 0
3 years ago
A Starting substance in a chemical reaction is called a _______________.
djverab [1.8K]

Answer:

1.)REACTANT

  • These starting substances of a chemical reaction are called the <em>reactants</em>, and the new substances that result are called the products.
5 0
3 years ago
[04.02]What coefficients must be added to balance the following equation?
vesna_86 [32]
<span>Methink this is a neutralization reaction where an acid reacts with a base to form salt and water; but if we must balance the equation, we need to know what the product would be? So our base LiOH reacts with our acid Tetraoxosulphate (VI) H2SO4. The reaction produces salt and water as evidence. LiOH + H2SO4 gives Li2SO4 and H20. We need to make sure that the total atoms on the LHS and RHS balanced. So adding two moles of LiOH, we have 2LiOH + H2SO4 produces LiSO4 + H20. The eqn isn't balanced yet as there's 2 moles of deficit H2 atoms on the RHS, So our final reaction we have 2LiOH + H2SO4 gives Li2SO4 + 2H2O. Hence our answer is C</span>
7 0
3 years ago
Look at the two thermometers.
salantis [7]

Answer:

Thermometer A, because it measures accurately to the tenths digit.

3 0
3 years ago
Read 2 more answers
The first step in industrial nitric acid production is the catalyzed oxidation of ammonia. Without a catalyst, a different react
murzikaleks [220]

<u>Answer:</u> The value of K_{eq} is 4.84\times 10^{-5}

<u>Explanation:</u>

We are given:

Initial moles of ammonia = 0.0280 moles

Initial moles of oxygen gas = 0.0120 moles

Volume of the container = 1.00 L

Concentration of a substance is calculated by:

\text{Concentration}=\frac{\text{Number of moles}}{\text{Volume}}

So, concentration of ammonia = \frac{0.0280}{1.00}=0.0280M

Concentration of oxygen gas = \frac{0.0120}{1.00}=0.0120M

The given chemical equation follows:

                  4NH_3(g)+3O_2(g)\rightleftharpoons 2N_2(g)+6H_2O(g)

<u>Initial:</u>        0.0280        0.0120

<u>At eqllm:</u>    0.0280-4x   0.0120-3x   2x       6x

We are given:

Equilibrium concentration of nitrogen gas = 3.00\times 10^{-3}M=0.003

Evaluating the value of 'x', we get:

\Rightarrow 2x=0.003\\\\\Rightarrow x=0.0015M

Now, equilibrium concentration of ammonia = 0.0280-4x=[0.0280-(4\times 0.0015)]=0.022M

Equilibrium concentration of oxygen gas = 0.0120-3x=[0.0120-(3\times 0.0015)]=0.0075M

Equilibrium concentration of water = 6x=(6\times 0.0015)]=0.009M

The expression of K_{eq} for the above reaction follows:

K_{eq}=\frac{[H_2O]^6\times [N_2]^2}{[NH_3]^4\times [O_2]^3}

Putting values in above expression, we get:

K_{eq}=\frac{(0.009)^6\times (0.003)^2}{(0.022)^4\times (0.0075)^3}\\\\K_{eq}=4.84\times 10^{-5}

Hence, the value of K_{eq} is 4.84\times 10^{-5}

4 0
3 years ago
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