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Anon25 [30]
4 years ago
7

If two firecrackers produce a sound level of 81 dBdB when fired simultaneously at a certain place, what will be the sound level

if only one is exploded?
Physics
1 answer:
Mrac [35]4 years ago
5 0

Answer:

77.96dB

Explanation:

Recall that decibels are a unit of measuring intensity of sound, and depend on the logarithm of the intensity

the intensity, measured in decibels is given by:

I(db)=10log(I/I0)

I is the intensity in MKS units; I0 is the threshold intensity for human hearing (10^-12 W/m^2)

Thus, if the two sounds together have a dB of 81, we know:

81=10log(I/I0)

using the data above, we can find the intensity of the two sounds to be

0.000125 W/m^2

therefore, one firecracker has an intensity half of that, or 0.0000625W/m^2

now use this value to find the dB of one firecracker:

I(dB0=10log(0.0000625/10^-12)=77.96dB

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If, in general, r were calculated as r =v/i, which circuit arrangement in part a of the experiment would have the smallest error
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Concept: According to Ohm's Law, the flow of electric current through a conductor is directly proportional to the potential difference across it, provided physical conditions (like temperature, pressure, volume etc.) remains same.

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In the given experiment, the first arrangement of the circuit will show the smallest error because the voltmeter is connected exactly parallel to the external resistance.

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3 years ago
What is the maximum number of lines per centimeter a diffraction grating can have and produce a complete first-order spectrum fo
emmainna [20.7K]

Answer:

14,300 lines per cm

Explanation:

Given that

The wavelength of visible light ranges from 400 nm to 400nm

It is possible to find the maximum number of lines per cm. This maximum number of lines per cm is reciprocal of the least distance separating two adjacent slits, using the following equation.

mλ = dsin (θ), where

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λ = wavelength of the incident light.

d = distance between the centers of the two slits.

θ = angle of diffraction of the mth order.

In order to find the least separation that allows the observation of one complete order of spectrum of the visible region, we make use the maximum or highest wavelength of the visible region that we are given, which is 700 nm.

d = mλ / sin (θ)

Again, we need the distance d to be the smallest, so sin (θ) must be the greatest, and for sin (θ) to be the greatest, it has to be equal to 1. Using the longest wavelength is the best idea because when the smallest wavelength is used the longest wavelength would not be diffracted.

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3 years ago
How much work is done if you push a 200 N box across a floor with a force of 50 N for a distance of 20m
vovikov84 [41]
<h2>Answer: 1000 J</h2>

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When they are not parallel, both directions form an angle, let's call it \alpha. In that case the expression to calculate the Work is:  

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For example, in order to push the 200 N box across the floor, you have to apply a force along the distance d to overcome the resistance of the weight of the box (its 200 N).  

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Hence:

W=(50N)(20m)  

W=1000Nm=1000J >>>>This is the work  

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