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4 years ago

14

These clouds often cover the sky and may bring light rain or snow. (4 points) Select one: a. Cirrus b. Stratus c. Cumulus d. Cul

umnar

1 answer:

Ludmilka [50]4 years ago

4 0

the answer is c. cumulus

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An individual white LED (light-emitting diode) has an efficiency of 20% and uses 1.0 W of electric power. a. How many LEDs must

Neporo4naja [7]

Answer:

8, 8 W

Explanation:

The useful power of 1 Light Emitting Diode is

$0.2\times 1=0.2\ W$

Total power required is 1.6 W

Number of Light Emitting Diodes would be

$n=\dfrac{1.6}{0.2}\\\Rightarrow n=8$

The number of Light Emitting Diodes is 8.

Power would be

$P=8\times 1=8\ W$

The power that is required to run the Light Emitting Diodes is 8 W

7 0

4 years ago

Help! I can't remember how to calculate this.

Mars2501 [29]

You need to draw two lines from the head of the arrow: one parallel to the axis (which will be bent) and the other one passing through the center of the converging lens <span>(which will continue straight) </span>and see where they intersect.

If the arrow is at an infinite distance, the image will be point-like in F.
If the arrow is at a distance greater than 2F, the image will be upside down between F and 2F.
If the arrow is at a distance of 2F, the image will be upside down in 2F.
If the arrow is at a distance between F and 2F, the image will be upside down beyond 2F.
If the arrow is at a distance F, all rays proceed parallel to each other and no image is formed.
If the arrow is at a distance smaller than F, the image will be virtual.

Therefore, the correct matches are 1B, 2C, 3D, and 4A.

5 0

3 years ago

Explain how electric current is able to flow.

Evgen [1.6K]

Answer:through wires or cables

Explanation:

7 0

3 years ago

How much heat transfer is required to raise the temperature of a 0.750-kg aluminum pot containing 2.50 kg of water from 30.0ºC t

lorasvet [3.4K]

Answer:

Part a)

$Q = 2.47 \times 10^6$

Part b)

t = 4950.3 s

Explanation:

As we know that heat required to raise the temperature of container and water in it is given as

$Q = m_1s_2\Delta T_1 + m_2s_2\Delta T_2$

here we know that

$m_1 = 0.750$

$s_1 = 900$

$m_2 = 2.50 kg$

$s_2 = 4186$

$\Delta T_1 = \Delta T_2 = 100 - 30 = 70^oC$

now we have

$Q_1 = 0.750(900)(70) + (2.5)(4186)(70) = 779800 J$

now heat require to boil the water

$Q = mL$

here

m = 0.750 kg

$L = 2.25 \times 10^6 J/kg$

now we have

$Q_2 = 0.750(2.25 \times 10^6) = 1.7 \times 10^6 J$

Now total heat required is given as

$Q = Q_1 + Q_2$

$Q = 779800 + 1.7 \times 10^6 = 2.47 \times 10^6 J$

Part b)

Time taken to heat the water is given as

$t = \frac{Q}{P}$

here we know that

power = 500 W

now we have

$t = \frac{2.47 \times 10^6}{500} = 4950.3 s$

8 0

3 years ago

What is the difference between electric current and electric circuit?

tangare [24]

Current<span> is nothing but the flow of charges due to the potential </span>difference<span>, whether its an electronic </span>circuit<span> or an </span>electrical circuit<span>.

</span>

4 0

3 years ago

Read 2 more answers