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WARRIOR [948]
3 years ago
6

A force of 348.0 N is used to push a car 33.4 m horizontally in 3.21 s. Calculate the power developed.

Physics
1 answer:
Alekssandra [29.7K]3 years ago
7 0

Answer:

3620.9 Watts

Explanation:

So first you want to find the work (J) and to find the work you need to multiply force (N) times distance (m).

348.0*33.4=11623.2 J

After that you want to find the power (Watt) and to find the power you need to divide the work (J) by the time (s).

11623.2/3.21=3620.9 Watts

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Frequencies of sound waves higher than those we can hear is called?
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Answer:

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Given the frequency of an electromagnetic wave, what else can you find immediately?
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Answer:

wavelength

Explanation:

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If the frequency of electromagnetic wave is unknown then we find the wavelength of wave. the formula used is

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3 years ago
A) A spaceship passes you at a speed of 0.800c. You measure its length to be 31.2 m .How long would it be when at rest?
rosijanka [135]

Answer:

a

     l_o  =52 \  m

b

      l = 37.13 \ LY

Explanation:

From the question we are told that

    The  speed of the spaceship is  v  =  0.800c

    Here  c is the speed of light with value  c =  3.0*10^{8} \ m/s

    The  length is  l = 31.2 \  m

     The  distance of the star for earth is d = 145 \  light \  years

     The  speed is v_s = 2.90 *10^{8}

     

Generally the from the length contraction equation we have that

       l  =  l_o  \sqrt{1 -[\frac{v}{c } ]}

Now the when at rest the length is  l_o

So  

      l_o =\frac{l}{\sqrt{ 1 - \frac{v^2}{c^2 } } }

      l_o =\frac{ 31.2 }{ \sqrt{1 - \frac{(0.800c ) ^2}{c^2} } }

      l_o=52 \  m

Considering b  

  Applying above equation

            l  =l_o \sqrt{1 -  [\frac{v}{c } ]}

Here l_o  =145 \  LY(light \ years )

So

           l=145 *  \sqrt{1 -  \frac{v_s^2}{c^2 } }

            l =145 *  \sqrt{ 1 - \frac{2.9 *10^{8}}{3.0*10^{8}} }

            l = 37.13 \ LY

4 0
3 years ago
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evablogger [386]

Answer:

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Explanation:

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