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Strike441 [17]
3 years ago
11

Does this want to know greater than, less than or equal?

Mathematics
2 answers:
MArishka [77]3 years ago
6 0
Think of a number line when solving this. The negative numbers are lower in value than the positive side.
a. greater than
b. greater than
c. greater than
d. equal to
e. less than
f. less than
Hope this helps!
myrzilka [38]3 years ago
4 0
I'm believing you want question 3 answer if so:
a 3> -7
b. -8>-10
c. 12>-11
d. 7=7
e.-4<0
f.0<5
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Can Someone plz help? Thx
Andreyy89

Answer:

7. 2355 m

8. 1570 km

9. 157 cm

10. 40.82 m

Step-by-step explanation:

The circumference of a circle is pi * diameter or 2 * pi * radius.

If you are given the diameter, just multiply it by pi, 3.14.

If you are given the radius, then multiply the radius by 2 and then by pi, 3.14.

7. d = 750 m

circumference = pi * d = 3.14 * 750 m = 2355 m

8. d = 500 km

circumference = pi * d = 3.14 * 500 km = 1570 km

9. r = 25 cm

circumference = 2(pi)r = 2 * 3.14 * 25 cm = 157 cm

10. r = 6.5 m

circumference = 2(pi)r = 2 * 3.14 * 6.5 m = 40.82 m


8 0
3 years ago
Jill says that 1 2/3 equals 3:5 is Jill correct
Reika [66]

Answer:

<em>Not true. Actually, 1 2/3 equals 5/3.</em>

5 0
3 years ago
Read 2 more answers
I NEED HELP!! please show all work
PtichkaEL [24]

Take the logarithm of both sides. The base of the logarithm doesn't matter.

4^{5x} = 3^{x-2}

\implies \log 4^{5x} = \log 3^{x-2}

Drop the exponents:

\implies 5x \log 4 = (x-2) \log 3

Expand the right side:

\implies 5x \log 4 = x \log 3 - 2 \log 3

Move the terms containing <em>x</em> to the left side and factor out <em>x</em> :

\implies 5x \log 4 - x \log 3 = - 2 \log 3

\implies x (5 \log 4 - \log 3) = - 2 \log 3

Solve for <em>x</em> by dividing boths ides by 5 log(4) - log(3) :

\implies \boxed{x = -\dfrac{ 2 \log 3 }{ 5 \log 4 - \log 3 }}

You can stop there, or continue simplifying the solution by using properties of logarithms:

\implies x = -\dfrac{ \log 3^2 }{ \log 4^5 - \log 3 }

\implies x = -\dfrac{ \log 9 }{ \log 1024 - \log 3 }

\implies \boxed{x = -\dfrac{ \log 9 }{ \log \frac{1024}3 }}

You can condense the solution further using the change-of-base identity,

\implies \boxed{x = -\log_{\frac{1024}3}9}

5 0
3 years ago
Help me please due tommorow
PIT_PIT [208]
To help you you should find a common denominator and then the fraction that has lower numbers is bigger
3 0
3 years ago
3x−8 ≤ 23 OR −4x+26≥6 find x
ElenaW [278]

Answer:

3x-8<=23

3x<=23+8

3x< =31

X< = 10.3

or

-4x+26>=6

-4x>=-20

X>=5

6 0
3 years ago
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