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iren2701 [21]
4 years ago
6

Estimate and classify the critical points for the graph of each function.

Mathematics
1 answer:
Neko [114]4 years ago
6 0

Answer: B

(0.5, 7), maximum; (2, 1), point of inflection; (3.5, –5), minimum

Critical points of a function are those points at which a line drawn tangent to the curve is horizontal or vertical. On the graph, maximum and minimum points look like peaks and valleys, respectively. Points of inflection that are critical points are places where the curve flattens out and changes from being bent upward to being bent downward or vice versa.

Just passed the test

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Let X be a Binomial Random Variable with 8 trials and a probability of success as 0.37. Suppose you want to find k such that P(X
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Answer:

k = 4

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 8, p = 0.37. So

P(X < k) = 0.6625

k only assumes discrete values, so

P(X < k) = P(X \leq k-1) = 0.6625

We have to find the cummulative distribution until we hit 0.6625. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{8,0}.(0.37)^{0}.(0.63)^{8} = 0.0248

P(X \leq 0) = P(X = 0) = 0.0248

P(X = 1) = C_{8,1}.(0.37)^{1}.(0.63)^{7} = 0.1166

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0248 + 0.1166 = 0.1414

P(X = 2) = C_{8,2}.(0.37)^{2}.(0.63)^{6} = 0.2397

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0248 + 0.1166 + 0.2397 = 0.3811

P(X = 3) = C_{8,3}.(0.37)^{3}.(0.63)^{5} = 0.2814

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0248 + 0.1166 + 0.2397 + 0.2814 = 0.6625

P(X \leq 3) = P(X < 4) = 0.665

So k = 4

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Step-by-step explanation:

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