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dezoksy [38]
3 years ago
14

I really do not know how to do this, I already asked my teacher to explain it to me, but I still don’t understand. Can someone p

lease help me I would be very grateful.

Chemistry
1 answer:
Gala2k [10]3 years ago
3 0

1. to calculate molar mass , you need average atomic mass of each element.

formula is simple

suppose we have Na2CO3

here it says

there are

2 atoms of Na

1 atom of C

3 atom of O

now

molar mass = (total atoms of Na × average atomic mass of Na) + ( total atom of C × average atomic mass of C )+ (total atom of O × average atomic mass of O)

i hope you can figure out it now.

in case of (NH4)2

this means you have 2 count of NH4

so total atoms of N = 2

total atoms of H = 4×2 = 8

so on you can now figure it out

2. balanced equation

here LHS and RHS shoild have same number of atoms of each element .

for example

H2 + Cl2 => 2HCl

here 2 atoms of H combined with 2 atoms of Cl , we know H and Cl combined and formed HCl now because total H atoms are 2 and Cl atoms are 2 in LHS then we should also have 2 atoms of each in right side

so thats why we have 2HCl in right side.

Try to figure out . let me know if need any help

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oksian1 [2.3K]

Answer:

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Explanation:

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reversible adiabatic compression:

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∴ q = 0

∴ w = - PδV

⇒ δU = δw

⇒ CvδT = - PδV

ideal gas:

⇒ PδV + VδP = RδT

⇒ PδV = RδT - VδP = - CvδT

⇒ RδT - RTn/PδP = - CvδT

⇒ (R + Cv,m)∫δT/T = R∫δP/P

⇒ [(R + Cv,m)/R] Ln (T2/T1) = Ln (P2/P1) = Ln (1 E6/1 E5) = 2.303

∴ (R + Cv,m)/R = (R + (3/2)R)/R = 5/2R/R = 2.5

⇒ Ln(T2/T1) = 2.303 / 2.5 = 0.9212

⇒ T2/T1 = 2.512

∴ T1 = 298 K

⇒ T2 = (298 K)×(2.512)

⇒ T2 = 748.66 K

⇒ ΔU = Cv,mΔT

⇒ ΔU = (3/2)R(748.66 - 298)

∴ R = 8.314 J/K.mol

⇒ ΔU = 5620.26 J

⇒ w = 5620.26 J

  • H = U + nRT

⇒ ΔH = ΔU + nRΔT

⇒ ΔH = 5620.26 J + (1 mol)(8.314 J/K.mol)(450.66 K)

⇒ ΔH = 5620.26 J + 3746.787 J

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