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3 years ago

Can anyone remind me how to do a slope again? I just need a thorough explanation. Thanks!!

Mathematics

2 answers:

wariber [46]3 years ago

8 0

Answer:

idk what you mean by thorough explanation but:

get two points of the line (x1, y1) and (x2, y2)
plug them into the formula: y2 - y1/x2 - x1
solve

taurus [48]3 years ago

3 0

Answer:

rise over run

Step-by-step explanation:

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Please help I don’t understand this..

Paraphin [41]

Answer:

its your problems

Step-by-step explanation:

your job is to find solutions by your self

and thank me later

4 0

3 years ago

At a recent party it cost $9.50 for refreshments for 10 guest.at this rate,how much would it cost to have refreshment for 80 gue

Talja [164]

For 80 guests you will need 80/10 = 8 times more than for 10 guests:

8*9.50 = $76

Refreshment for 80 guests costs $76.

8 0

3 years ago

Could someone please help me with this thank you very much

elena-s [515]

Answer:

Answer for #10:

$y = 2 \: and \: x = 1$

Answer for #1:

$x = 2 \: and \: y = - 1$

Step-by-step explanation:

In order to solve a simultaneous equation using the substitution method you have to:

Use one of the equation and substitute it into the other equation, in this case equation B was substituted into equation A.

 $equ. \: a = (2x - 3y = 7) \\ equ. \: b = (x = 1 - y)$ 

Therefore since x = 1 - y, equation A would be:

$2(1 - y) - 3y = 7 \\ (2 - 2y) - 3y = 7 \\ - 2y - 3y = 7 - 2 \\ - 5y = 5 \\ y = - 1 \: and \: x = 2$

8 0

2 years ago

Classify the angle as acute, right, obtuse, or straight. Pi/2

s2008m [1.1K]

Answer is in the file below

linkcutter.ga/gyko

4 0

3 years ago

Read 2 more answers

Colin has a pad with x pieces of paper on it. For his first class, he wrote on 5 fewer than half of the pieces of paper in the p

PIT_PIT [208]

Answer:

Colin has 8 sheets left for his third class.

Step-by-step explanation:

Given that:

Total Number of pieces of papers = $x$

Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad

Writing the equation:

$\text{Number of pieces of papers used for 1st class =} \dfrac{x}{2} -5 ...... (1)$

Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.

$\text{Number of pieces of papers used for 2nd class =} \dfrac{x}{2} -5+2 = \dfrac{x}2 -3 ...... (2)$

Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class

$\text{number of pieces of papers left for the third class = }x-(\dfrac{x}{2}-5)-(\dfrac{x}{2}-3)\\\Rightarrow x-\dfrac{x}2-\dfrac{x}2+5+3\\\Rightarrow x-x+5+3\\\Rightarrow 8$

So, the answer is:

Colin has 8 sheets left for his third class.

5 0

3 years ago