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IRINA_888 [86]
3 years ago
9

Which types of clouds are bright white ad fluffy,sometimes forming shapes or pictures?

Chemistry
1 answer:
lawyer [7]3 years ago
4 0
The answer is cumulus. 

Stratus clouds often low and sometimes confused for fog. Cirrus clouds are thin and wispy.
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Fill in the blanks and balance with the correct coefficient​
MrRissso [65]

\huge\mathrm{  \underline{Answer}}࿐

The Balanced equation will be :

\mathrm{ \boxed2Fe +  \boxed3Cl_2  \rightarrow  \boxed2FeCl_3}

The Coefficients are :

  • Fe - 2

  • Cl_2 - 3

  • FeCl_3 - 2

_____________________________

\mathrm{ \#TeeNForeveR}

4 0
3 years ago
Manganese dioxide (MnO2(s), Hf = –520.0 kJ) reacts with aluminum to form aluminum oxide (AI2O3(s), Hf = –1699.8 kJ/mol) and mang
Temka [501]

Answer : The enthalpy of the reaction = -1839.6 KJ

Solution : Given,

\Delta (H_{f})_{MnO_{2}} = -520.0 KJ/mole

\Delta (H_{f})_{Al_{2}O_{3}} = -1699.8 KJ/mole

The balanced chemical reaction is,

3MnO_{2}(s)+4Al(s)\rightarrow 2Al_{2}O_{3}(s)+3Mn(s)

Formula used :

\Delta (H_{f})_{reaction}=\sum n(\Delta H_{f})_{product}-\sum n(\Delta H_{f})_{reactant}

\Delta (H_{f})_{reaction}=(2\times \Delta H_{Al_{2}O_{3}(s)}+3\times \Delta H_{Mn(s)} )-(3\times \Delta H_{MnO_{2}(s) }+4\times\Delta H_{Al}(s))

We know that the standard enthalpy of formation of the element is equal to Zero.

Therefore, the enthalpy of formation of (Mn) and (Al) is equal to zero.

Now, put all the values in above formula, we get

\Delta (H_{f})_{reaction}=[2moles\times (-1699.8 KJ/mole)}+3moles\times (0\text{ KJ/mole}})]-[(3moles\times(-520.0KJ/mole }+4moles\times(0\text{ KJ/mole})]

                        = (-3399.6) + (1560)

                        = -1839.6 KJ



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Which elements, when they have to, can have more than
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Elements in the third row can break the octet rule
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What does plasma mean
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How is burning wood a good illustration of the law of conservation of mass?
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The wood turns into ash and smoke so mass is nor destroyed or created.
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