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3 years ago

Which types of clouds are bright white ad fluffy,sometimes forming shapes or pictures?

Chemistry

1 answer:

lawyer [7]3 years ago

4 0

The answer is cumulus.

Stratus clouds often low and sometimes confused for fog. Cirrus clouds are thin and wispy.

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Please help i am losing motivation and very depressed please look at photo and answer.

iris [78.8K]

Answer:

Solid turns to liquid.

Explanation:

When you freeze water, it turns into ice. When melted it's still water. No chemical changes were made to the piece of ice melted. The only change was ice (solid) to water (liquid)

Conservation of Matter - Matter can change forms through physical and chemical changes, but no matter what, matter is conserved. The same amount of matter exists before and after the change.

Hope this helps! Please mark brainliest!

5 0

3 years ago

The atomic number of silicon (Si) is 14. What's the electron configuration for silicon? Question 1 options:

Tom [10]

Answer:

[Ne] 3S2 3P2

Explanation:

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8 0

3 years ago

Which is not a functional group A. Carboxyl B. Halide C. Hydroxyl D. Protein

xeze [42]

I believe it’s B. Halide

7 0

3 years ago

PLEASEEEE HELPPPPP!!!

Fantom [35]

Explanation:

Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams. pH+pOH=14⇒pH=14-3=

5 0

3 years ago

H2(g) + F2(g)2HF(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 2.20 moles

abruzzese [7]

Answer: The value of $\Delta S^o$ for the surrounding when given amount of hydrogen gas is reacted is -31.02 J/K

Explanation:

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

$\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]$

For the given chemical reaction:

$H_2(g)+F_2(g)\rightarrow 2HF(g)$

The equation for the entropy change of the above reaction is:

$\Delta S^o_{rxn}=[(2\times \Delta S^o_{(HF(g))})]-[(1\times \Delta S^o_{(H_2(g))})+(1\times \Delta S^o_{(F_2(g))})]$

We are given:

$\Delta S^o_{(HF(g))}=173.78J/K.mol\\\Delta S^o_{(H_2)}=130.68J/K.mol\\\Delta S^o_{(F_2)}=202.78J/K.mol$

Putting values in above equation, we get:

$\Delta S^o_{rxn}=[(2\times (173.78))]-[(1\times (130.68))+(1\times (202.78))]\\\\\Delta S^o_{rxn}=14.1J/K$

Entropy change of the surrounding = - (Entropy change of the system) = -(14.1) J/K = -14.1 J/K

We are given:

Moles of hydrogen gas reacted = 2.20 moles

By Stoichiometry of the reaction:

When 1 mole of hydrogen gas is reacted, the entropy change of the surrounding will be -14.1 J/K

So, when 2.20 moles of hydrogen gas is reacted, the entropy change of the surrounding will be = $\frac{-14.1}{1}\times 2.20=-31.02J/K$

Hence, the value of $\Delta S^o$ for the surrounding when given amount of hydrogen gas is reacted is -31.02 J/K

7 0

3 years ago