Answer:
Exothermic, it obeys the law of conservation of energy
Explanation:
The reaction is an exothermic change. In this kind of change, heat is liberated to the surrounding. So the surrounding becomes hotter at the end of the heat change.
In chemical reactions that involves the loss of energy as heat, they obey the law of conservation of energy.
The law of conservation of energy states that energy is neither created nor destroyed but transformed from one form to another. In such reactions as this, chemical energy is transformed into heat energy.
Answer:
1.9 L
Explanation:
Step 1: Given data
- Initial number of moles of air (n₁): 4.0 mol
- Initial volume of the balloon (V₁): 2.5 L
- Final number of moles of air (n₂): 3.0 mol
- Final volume of the balloon (V₂): ?
Step 2: Calculate the final volume of the balloon
According to Avogadro's law, the volume of an ideal gas is directly proportional to the number of moles. We can calculate the final volume of the balloon using the following expression.
V₁ / n₁ = V₂ / n₂
V₂ = V₁ × n₂ / n₁
V₂ = 2.5 L × 3.0 mol / 4.0 mol
V₂ = 1.9 L
Answer:
1. When observing a positive test for the jones reagent and negative for the Lucas test, it indicates that it is in the presence of a primary alcohol.
Jones reagent behaves like a strong oxidant, where it transforms the primary alcohols into carboxylic acids and the secondary alcohols into ketones. Tertiary alcohols do not react.
With the Lucas test, tertiary alcohols react immediately producing turbidity, while secondary alcohols do so in five minutes. Primary alcohols do not react significantly with Lucas reagent at room temperature.
2. No reaction (See the attached drawing)
3. (see the attached drawing)
Answer:
28.8km/h
Explanation:
Change the 5min to hours.
=5/60 =0.0833hrs
Velocity= Distance /Time
2.4/0.0833
=28.8km/h
When methane is burned with oxygen, the products are carbon dioxide and water. If you produce 9 grams of water and 11 grams of carbon dioxide from 16 grams of oxygen, how many grams of methane were needed for the reaction? First you need to write a balanced chemical equation.
