Answer:
pH = 2.059
Explanation:
At the Cathode:
The reduction reaction is:
At the anode:
At oxidation reaction is:
The overall equation for the reaction is:
The overall cell potential is:
Using the formula for the Nernst equation:
where;
E = 0.66
(Zn^2+)=0.22 M
Then
![0.66 =0.76- ( \dfrac{0.0591}{2})log \bigg ( \dfrac{[Zn^{2+} ] PH_2}{[H^+]^2} \bigg )](https://tex.z-dn.net/?f=0.66%20%3D0.76-%20%28%20%5Cdfrac%7B0.0591%7D%7B2%7D%29log%20%5Cbigg%20%28%20%5Cdfrac%7B%5BZn%5E%7B2%2B%7D%20%5D%20PH_2%7D%7B%5BH%5E%2B%5D%5E2%7D%20%5Cbigg%20%29)
![0.66 =0.76- 0.02955 * log \bigg ( \dfrac{0.22*0.87}{[H^+]^2} \bigg )](https://tex.z-dn.net/?f=0.66%20%3D0.76-%200.02955%20%2A%20log%20%5Cbigg%20%28%20%5Cdfrac%7B0.22%2A0.87%7D%7B%5BH%5E%2B%5D%5E2%7D%20%5Cbigg%20%29)
3.4 = log ( 0.1914) - 2 log [H⁺]
3.4 = -0.7180 - 2 log [H⁺]
3.4 + 0.7180 = - 2 log [H⁺]
4.118 = - 2 log [H⁺]
pH = log [H⁺] = 4.118/2
pH = 2.059
Answer:
Partial pressure
Explanation:
the scientists is measuring different pressure, so it would be partial pressure. Hope that this helps you and have a great day :)
Answer:
This process is known as doping. It can be done by adding either of two types of impurity to the crystal. (A) By adding electron rich impurities i.e., group 15 elements to the silicon and germanium of group 14 elements.
Ernest Rutherford's gold foil experiment was when he shot positively charged particles at a thin layer of gold foil. He concluded that there was a core that contained most of the atom's mass, the core is the nucleus
This statement would be best characterized by the law of conservation of momentum—choice C.
