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3 years ago

How many valence electron do silver have

2 answers:

6 0

Silver has 1 valence electron. In terms of orbitals, it has the following electron configuration: 4d^10,5s^1. Due to the single electron in the 5s orbital it tends to lose it forming a 1+ ion.

Gnesinka [82]3 years ago

5 0

Silver has only 1 valence electron.

The electron configuration of Silver gives one outer shell electron, basically a valence electron.

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For an ideal gas, classify the pairs of properties as directly or inversely proportional. You are currently in a sorting module.

vredina [299]

Answer:

the result for the following are (a) P is directly proportional to n

(b) V is directly proportional to T (c) P is directly proportional to T (d) T is inversly proportional to V (e) P is inversely proportional to V

6 0

2 years ago

The rock in a lead ore deposit contains 89 % PbS by mass. How many kilograms of the rock must be processed to obtain 1.5 kg of P

Zolol [24]

Answer:

Approximately 1.9 kilograms of this rock.

Explanation:

Relative atomic mass data from a modern periodic table:

Pb: 207.2;
S: 32.06.

To answer this question, start by finding the mass of Pb in each kilogram of this rock.

89% of the rock is $\rm PbS$ . There will be 890 grams of $\rm PbS$ in one kilogram of this rock.

Formula mass of $\rm PbS$ :

$M(\mathrm{PbS}) = 207.2 + 32.06 = 239.26\; g\cdot mol^{-1}$ .

How many moles of $\rm PbS$ formula units in that 890 grams of $\rm PbS$ ?

$\displaystyle n = \frac{m}{M} = \rm \frac{890}{239.26} = 3.71980\; mol$ .

There's one mole of $\rm Pb$ in each mole of $\rm PbS$ . There are thus $\rm 3.71980\; mol$ of $\rm Pb$ in one kilogram of this rock.

What will be the mass of that $\rm 3.71980\; mol$ of $\rm Pb$ ?

$m(\mathrm{Pb}) = n(\mathrm{Pb}) \cdot M(\mathrm{Pb}) = \rm 3.71980 \times 207.2 = 770.743\; g = 0.770743\; kg$ .

In other words, the $\rm PbS$ in 1 kilogram of this rock contains $\rm 0.770743\; kg$ of lead $\rm Pb$ .

How many kilograms of the rock will contain enough $\rm PbS$ to provide 1.5 kilogram of $\rm Pb$ ?

$\displaystyle \frac{1.5}{0.770743} \approx \rm 1.9\; kg$ .

5 0

3 years ago

The measurement of grams of solute per one million grams of solution is known as

Zinaida [17]

I think it's Molality because the moles of solute over the kilograms of solvent is equal to the molality...

5 0

3 years ago

Which of the following best explains why the two values in Parts A and B are different? The perceived forces between chlorine ga

BartSMP [9]

Answer:

The high system pressure and relatively large chlorine molecule size.

Explanation:

Having the expression of the ideal gas, and clearing the pressure, we have:

P = nRT/V

Meanwhile, for a non-ideal gas we have the following equation:

P = (nRT / V-nb) - n2a/V2

In this equation, high pressures and low temperatures have an influence on nonideal gases.

Therefore, at high pressures, the molecules in a gas are closer together and have high intermolecular forces. On the other hand, at low temperatures, the kinetic energy of a gas is reduced, so that the intermolecular attractive forces are also reduced.

6 0

2 years ago

Read 2 more answers

Last week you reacted magnesium with a hydrochloric acid aqueous solution and hydrogen gas was produced. Let's say that you coll

miv72 [106K]

Answer:

69.8 kilo Pasacl is the pressure of the hydrogen gas.

Explanation:

$Mg+2HCl\rightarrow MgCl_2+H_2$