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Katen [24]
3 years ago
14

What is the density of a liquid if the volume is 25 mL and the mass is 20 g? *

Chemistry
2 answers:
DENIUS [597]3 years ago
8 0

Answer:

density =mass/volume

Explanation:

volume is in mL

convert it into cm³

0.000025cm³

density=20/0.000025

20×10 power 6/25

0.8×10 power 6 g/cm³

or

0.8 g/ml

spin [16.1K]3 years ago
3 0

Answer: Density = 0.8 g/mL

Explanation: Density is the ratio between mass per unit volume

D= m/V

= 20 g / 25 mL

= 0.8 g/ mL

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What is the percent yield of the purification system
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3 years ago
Al2(SO4)3+Mg(NO3)2⟶ What would be the product(s) of this reaction? *These are NOT balanced, just look for the correct products*
Readme [11.4K]

Answer:

Al_2(SO_4)_3+3Mg(NO_3)_2\rightarrow 2Al(NO_3)_3+3MgSO_4

Explanation:

Hello there!

In this case, for the given reactants side, we infer this is a double replacement reaction because all the cations and anions are switched around as a result of the chemical change, we infer that the products side include aluminum with nitrate and magnesium with sulfate as shown below:

Al_2(SO_4)_3+Mg(NO_3)_2\rightarrow Al(NO_3)_3+MgSO_4

However, we need to balance since unequal number of atoms are present at both sides, thus, we do that as shown below:

Al_2(SO_4)_3+3Mg(NO_3)_2\rightarrow 2Al(NO_3)_3+3MgSO_4

Thus, we make 6 Al atoms, 3 S atoms, 3 Mg atoms and 30 O atoms on each side in agreement with the law of conservation of mass.

Regards!

7 0
3 years ago
8. A 220 mL sample of helium gas is in a cylinder with a movable piston at 105 kPa and 275K. The piston
Harrizon [31]

The sample has a new pressure of 274kPa. If at 105 kPa and 275K, a 220 mL sample of helium gas is contained in a cylinder with a moving piston. The sample is pushed till it has a 95.0 mL volume and 310K .

The macroscopic characteristics of ideal gases are related by the ideal gas law (PV = nRT). A gas is considered to be perfect if its particles (a) do not interact with one another and (b) occupy no space (have no volume). Where P= pressure  V= volume and T = temperature.

From ideal gas equation

P₁V₁/T₁ =P₂V₂/T₂

105×220÷275 = P₂ ×95÷310

P₂= (105×220×310)÷(275×95)

P2= 7161000/26125

P2 = 274.105 kPa

Hence, the new pressure of helium gas is 274kPa

To know more about Ideas gas equation

brainly.com/question/28837405

#SPJ1

8 0
1 year ago
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