A positive charge Q is placed at the origin. Four other positive charges are placed on a circle in the x-y plane centered on Q a
1 answer:
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Answer:
(a) Time to reach maximum height,
(b) Time to reach the ground,
(c) Maximum height,
(d) Total horizontal distance,
Explanation:
According to the problem, v₀ is initial speed, g is acceleration due to gravity and θ is angle with respect to the horizontal.
The horizontal and vertical components of the initial speed are v₀cosθ and v₀sinθ respectively.
There is no acceleration acting horizontally on the projectile but there is vertical acceleration g is acting on the projectile.
(a) The equation of motion along vertical direction is:
v = v₀sinθ - gt
At maximum height, the speed of projectile is zero i.e.v is zero in the above equation. Thus, the above equation becomes :
(b) The time at which projectile hits the ground is :
....(1)
(c) The equation of motion along vertical direction is :
v² = (v₀sinθ)² - 2gs
Here s is the vertical height of the projectile.
At maximum height H, v is zero. So, the above equation becomes :
(d) The equation of motion along horizontal is :
x = (v₀cosθ)t
Here x is horizontal distance travel by projectile.
The total distance (R) traveled by projectile is :
Substitute the equation (1) in above equation.
Using trigonometry relation:
2sinθcosθ = sin2θ