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alexgriva [62]
3 years ago
9

A careful photographic survey of Jupiter's moon Io by the spacecraft Voyager 1 showed active volcanoes spewing liquid sulfur to

heights of 70 km above the surface of this moon. If the value of g on Io is 2.0 m/s2 , estimate the speed with which the liquid sulfur left the volcano.
Physics
1 answer:
Over [174]3 years ago
6 0

The concept used to solve this problem is that given in the kinematic equations of motion. From theory we know that the change in velocities of a body is equivalent to twice the distance traveled by acceleration, in other words:

v_f^2-v_i^2 = 2ax

Where,

v_{f,i} = Final and initial velocity

a = Acceleration

x = Displacement

For the given case, the displacement is equivalent to the height (x = h) and the acceleration is the same gravitational acceleration (a = g). In turn we do not have initial speed therefore

v_f^2 = 2hg

v_f = \sqrt{2hg}

Our values are given as

h = 70km = 70*10^3m

g = 2m/s^2

Replacing we have that,

v_f = \sqrt{2hg}

v_f = \sqrt{2(70*10^3)(2)}

v_f = 529.15m/s

Therefore the speed with which the liquid sulfur left the volcano is 529.15m/s

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