Question

The surface tension of a liquid is to be measured using a liquid film suspended on a U-shaped wire frame with an 12-cm-long movable side. If the force needed to move the wire is 0.096 N, determine the surface tension of this liquid in air.

Answer 1

Answer:

σ  = 0.8 N/m

Explanation:

Given that

L = 12 cm

We know that 1 m = 100 cm

L = 0.12 m

The force ,F= 0.096 N

Lets take surface tension = σ

We know that surface tension is given as

$\sigma =\dfrac{F}{L}\\\sigma =\dfrac{F}{L}\\Now\ by\ putting\ the\ values\\\sigma =\dfrac{0.096}{0.12}\ N/m\\\sigma=0.8\ N/m$

Therefore the surface tension σ  will be 0.8 N/m .

σ  = 0.8 N/m