Question

The diffraction phenomenon can be observed whenever the wavelength is comparable in magnitude to the size of the slit opening. To be "diffracted," how fast must a person weighing 84 kg move through a door 1 m wide

Answer 1

Answer:

Velocity,$v=7.89\times10^{-36}m/s$

Explanation:

Diffraction will only occur when the wavelength,$\lambda$, is comparable in size to the slit opening. Given the,$\lambda=1m,$,and mass of the person as $84kg$, we can apply

De-Broglie equation, to obtain the velocity.

$\lambda=\frac{h}{mv}\\v=\frac{6.626\times10^{-34}Js}{84kg\times1m}\\v=7.89\times10^{-36}m/s$

The velocity of the person is $7.89\times10^{-36}m/s$