Answer:
a) 15.77 m/sec2
b) 13.3 deg
Explanation:
we are given;
Flea force = F1=1.07×10⁻5 N j
Breeze force = F2 = 1.14× 10⁻6 N (-j
mass of flea =6.0 ×10⁻7 kg
So net force on the flea=F1+F2+weight of flea=1.07×10⁻5 j +1.14× 10⁻6 i + 6.0 ×10⁻7 (-j) ×9.8= ma
==> ma = 1.07×10⁻5 j - 0.588×10⁻5 j + 0.114×10⁻5 i
==> ma= 0.482 ×10⁻5 j +0.114×10⁻5 i
==> ma = 0.114×10⁻5 i +0.482 ×10⁻5 j
== a = (0.114×10⁻5 i +0.482 ×10⁻5 j) / 6.0 ×10⁻7
==> a =
==>a= (1.9 j+8.03 i ) m/sec2
mag of a 
= 15.77 m/sec2
direction angle = tan⁻1(1.9/8.03)=13.3°
The value of t for which the particle is at rest is : t = 2
<u>Given data:</u>
X = t³ - 3t²
Y = 2t³ - 3t² - 12t
<h3>Determine the values of t for which the particle is at rest </h3>
<u>First step : Determine the first derivative of eac equations</u>
dx = 3t² - 6t
dy = 6t² - 6t - 12
<u>Next step : </u><u>determine</u><u> the value of slope ( dy/dx ) = o </u>
dy / dx = ( 6 (t² - t - 2) ) / ( 3t ( t - 2) )
Therefore
dy / dx = ( 2 ( t + 1 ) (t - 2) ) / ( t ( t -2) )
= 0
Therefore at ; t = -1 and 2 the particle is at rest
Hence we can conclude that Neglecting the negative value the particle will be at rest when t = 2
Learn more about Object at rest : brainly.com/question/24160573
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<u>Attached below is the complete question</u>
<em>The position of a particle moving in the xy-plane is given by the parametric equations x = t3 - 3t2 and y = 2t3 - 3t2 - 12t. For what values of t is the particle at rest?</em>
The equation for Kinetic Energy is KE = 1/2 m v^2, where m is the mass, and v is the velocity. The velocity in this equation is squared, which means that it is exponential. That means that as the velocity increases, you will be multiplying by a bigger and bigger number! KE = 18 joules!
Physics is a type of science, like life science.
Answer:
100m
Explanation:
conversation km to meter
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