Answer:
V = 4.48m/s a = 1.57m/s²
Explanation:
ω₀ = 16rad/s
α₀ = 5.6rad/s²
r = 280mm = 0.28m
a = ?
v = ?
Angular velocity (ω₀) = velocity of acceleration / length of path
ω₀ = v / r
V = ω₀ * r
V = 16 * 0.28
V = 4.48m/s
Acceleration = ?
Angular acceleration α₀ = angular velocity (ω) / time take (t)
α₀ = ω / t .... equation i
But acceleration (a) = velocity (v) / time (t)
a = v / t
t = v / a
Put t = v / a into equation i
α₀ = ω / (v / a)
α₀ = ω * a / v
α * v = ω * a
a = (α * v) / ω
a = (5.6 * 4.48) / 16
a = 1.568m/s²
a = 1.57m/s²
Answer:
acceleration=(v final-vinitial)/time
a=(vf-vi)/t
2=(30-10)/t
2=20/t
t=20/2=10 seconds
distance=v0t+at²/2
d=10 x 10+ 2x 10²/2=100+100= 200 m
Explanation:
Answer:
Increase in wavelength of incident wave also increases the spread angle or spread of the interference pattern.
Explanation:
Solution:-
- The diffraction occurs when light bends in the same medium. The bending is the result of light waves "squeezing" through small openings or "curving" around sharp edges.
- Moreover, waves diffract best when the size of the diffraction opening (or grting or groove) corresponds to the size of the wavelength. Hence, light diffracts more through small openings than through larger openings.
- The formula for diffraction shows a direct relationship between the angle of diffraction (theta) and wavelength:
d sin (θ) = m λ
Where,
λ : Wavelength , θ : The spread angle , d : Slit opening or grating
- We can see that the wavelength λ and spread angle θ are related proportionally. So if we increase the wavelength of incident wave we also increase the spread angle or spread of the interference pattern.
