Answer:
Y = 92.5 %
Explanation:
Hello there!
In this case, since the reaction between lead (II) nitrate and potassium bromide is:
Exhibits a 1:2 mole ratio of the former to the later, we can calculate the moles of lead (II) bromide product to figure out the limiting reactant:
Thus, the limiting reactant is the KBr as it yields the fewest moles of PbBr2 product. Afterwards, we calculate the mass of product by using its molar mass:
And the resulting percent yield:
Regards!
I thinks it's true but I'm not sure
Answer:
Explanation:
121) The sugar sucrose has 12 carbon atoms, 22 hydrogen atoms and 11 oxygen
atoms. How would this be written?
A) Co12H22O1 [Co is cobalt]
<u><em>B) CI2H22011</em></u> [Yes]
C) C6H1206 [6 C atoms]
D) CacH1206 [Ca is calcium]
122) How are the elements organized on the periodic table?
A) Atomic Mass [Yes, from lightest to heaviest]
B) Element Name
C) Symbol
D) No Set Organization
123) Which of the following elements would be considered a compound?
A) CH [Yes, two or more elements combined]
B) Si [No]
C)F [No]
D) O6 [No, multiple atoms, but same element]
124) The formula for water is H2O meaning there are 2 Hydrogen atoms and 1
Oxygen. What is the atomic mass of one molecule to the nearest hundredth?
A) 15.99
B) 16.99
C) 17.99 [Yes, 16 + 2*1 = 18]
D) 18.99
Answer: 6.48m/s
Explanation:
From the question given, we obtained the following:
M = 50 kg
Velocity =?
Momentum = 324 kg•m/s
Momentum = Mass x Velocity
Velocity = momentum /Mass
Velocity = 324 / 50
Velocity = 6.48m/s
Answer:
[COF₂] = 0.346M
Explanation:
For the reaction:
2COF₂(g) ⇌ CO₂(g) + CF₄(g)
Kc = 5.70 is defined as:
Kc = [CO₂] [CF₄] / [COF₂]² = 5.70 <em>(1)</em>
Equilibrium concentrations of each compound after addition of 2.00M COF₂ will be:
[COF₂] : 2.00M - 2x
[CO₂] : x
[CF₄] : x
Replacing in (1):
5.70 = [X] [X] / [2-2x]²
22.8 - 45.6x + 22.8x² = x²
0 = -21.8x² + 45.6x - 22.8
Solving for x:
X = 1.265 <em>-False answer, will produce negative concentrations-</em>
<em>X = 0.827.</em>
Replaing, molar concentration of COF₂ is:
[COF₂] : 2.00M - 2×0.827 = <em>0.346M</em>
I hope it helps!
