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Zinaida [17]
3 years ago
9

A radioisotope has a half-life of 12 days. If a sample is measured to contain 5 grams of radioisotope, how much time has passed

if the sample originally measured 160 grams of radioisotope?​
Chemistry
1 answer:
Sophie [7]3 years ago
7 0
60 days have passed. In every 12 days the radioisotope loses half of its life. So in the first 12 days, from 160 grams it decreases to half so it becomes 80 grams. The second 12 days, from 80 grams, it decreases to half and becomes 40 g. The third 12 days, from 40 it becomes half to 20 g. The fourth 12 days, from 20 g it becomes half to 10 g. And in the fifth 12 days, from 10 g it becomes half to 5 grams. So 5 times it became half.
5 x 12 ( days)= 60 days
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Should a homeowner expect more caco3 buildup in hot water pipes or cold water pipes
Arturiano [62]
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             CaCO₃ built up in hot water pipes

Explanation:

The hardness of water is classified as;

Permanent Hard Water:
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                                        Calcium Sulfate  CaSO₄

                                        Calcium Chloride   CaCl₂

                                        Magnesium Sulfate   MgSO₄

                                        Magnesium Chloride   MgCl₂

These salts does not precipitate out on heating water.

Temporary Hard Water:
                                     In this water the mineral content can be removed by boiling. This water contains mainly following,

                                        Calcium Bicarbonate  Ca(HCO₃)₂

                                        Calcium Carbonate  CaCO₃

                                        Magnesium Bicarbonate   Mg(HCO₃)₂

                                        Magnesium Carbonate  MgCO₃

These salts does not precipitate out on heating water. i.e.

                Ca(HCO₃)₂    -------heat------>    CaCO₃  +  CO₂  +  H₂O

The CaCO₃ are formed in the form of scales.

Result:
           Hence, we can say that that CaCO₃ built up in hot water pipes.
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