Answer:
pH before addition of KOH = 4.03
pH after addition of 25 ml KOH = 7.40
pH after addition of 30 ml KOH = 7.57
pH after addition of 40 ml KOH = 8.00
pH after addition of 50 ml KOH = 10.22
pH after addition 0f 60 ml KOH = 12.3
Explanation:
pH of each case in the titration given below
(6) After addition of 60 ml KOH
Since addition of 10 ml extra KOH is added after netralisation point.
Concentration of solution after addition 60 ml KOH is calculated by
M₁V₁ = M₂V₂
or, 0.23 x 10 = (50 + 60)ml x M₂
or M₂ = 0.03 Molar
so, concentration of KOH = 0.03 molar
[OH⁻] = 0.03 molar
pOH = 0.657
pH = 14 - 0.657 = 13.34
Answer:-
Chlorine gas is passed through a solution of flower to
<u>decolourise the flower</u>
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Explanation:
Chlorine is used as a bleaching agent because of its oxidising nature.
This nascent "O" is highly reactive in nature and bleaches the substance that comes into its contact.
when flowers are passed through the chlorine solution , it oxidises the solution and removes the colour from the flower.
This property also made its use as water-disinfectant reagent.
Chlorination is done to make the water useful for drinking
It kills the harmful bacteria present in the water.
Answer:
weak acids have a pH of less than 2
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Answer:
shift to restore equilibrium
Explanation:
Le Châtelier's Principle states that when a stress is applied to a system at equilibrium, the system will respond by shifting in the direction (either towards the products or reactants side) that opposes/ minimizes the effect of the stress.
Note that although the system tries to restore equilibrium, this equilibrium is a new equilibrium.
Equilibrium is the state of a reversible reaction when:
• two opposing reactions occur at the same rate;
• the concentrations of reactants and products are constant