An electric heating element is connected to a 110 V circuit and a current of 3.2 A is flowing through the element. How much ener
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The magnitude of the centripetal acceleration of the car as it goes round the curve is 4.8 m/s²
<h3>Circular motion</h3>From the question, we are to determine the magnitude of the centripetal acceleration.
Centripetal acceleration can be calculated by using the formula
Where is the centripetal acceleration
is the velocity
and is the radius
From the given information
and
Therefore,
Hence, the magnitude of the centripetal acceleration of the car as it goes round the curve is 4.8 m/s²
Learn more on circular motion here: brainly.com/question/20905151
Answer:
27.1 m/s
Explanation:
Given that at a race car driving event, a staff member notices that the skid marks left by the race car are 9.06 m long. The very experienced staff member knows that the deceleration of a car when skidding is -40.52 m/s2.
Using third equation of motion,
V^2 = U^2 + 2aS
Since the car is decelerating, the final velocity V = 0
Substitute all the parameter into the equation above,
0 = U^2 - 2 * 40.52 * 9.06
U^2 = 734.22
U =
U = 27.096
U = 27.1 m/s approximately
Therefore, the staff member can estimate for the original speed of the race car to be 27.1 m/s if it came to a stop during the skid