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mart [117]
3 years ago
6

An electric heating element is connected to a 110 V circuit and a current of 3.2 A is flowing through the element. How much ener

gy is used up during a period of 5 hours by the element
Physics
2 answers:
UkoKoshka [18]3 years ago
6 0

Power (rate of using energy) = (voltage) x (current)

Power of this heating element = (120 V) x (3.2 A) = 384 watts


The easy way:

     384 watts = 0.384 kilowatt

     (0.384 kilowatt) x (5 hours) = 1.92 kilowatt-hour


Another way:
     
                            384 watts = 384 joules per second .

        (384 joule/sec) x (3600 sec/hour) x (5 hours)  

=      (384 x 3600 x 5) (joules)  =  6,912,000 joules.

dangina [55]3 years ago
6 0
Wouldn't it be 110V * 3.2A * 5 hours? 

The problem shows 110V not 120V

So it would be 110V * 3.2A = 352

And 352 * 5 = 1760
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tatuchka [14]

Answer:

3.90 degrees

Explanation:

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Since customer would not complain if the force is no more than 20N

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294.3sin\theta = 20

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\theta = sin^{-1}0.068 = 0.068 rad = 0.068*180/\pi \approx 3.90^0

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6 0
3 years ago
How can density be determined in a lab of a rectangular solid?
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Es frecuente que en las instalaciones eléctricas domésticas se utilice alambre de cobre de 2.05 mm de diámetro. Determine la res
Tasya [4]

Answer:

The resistance is 0.124 ohm.

Explanation:

It is common for domestic electrical installations to use copper wire with a diameter of 2.05 mm. Determine the resistance of such a wire with a length of 24.0 m.

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