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ololo11 [35]
3 years ago
14

If you experience a painful bee sting, there is formic acid at work. which type of organic compound is responsible for your suff

ering?

Chemistry
2 answers:
Lina20 [59]3 years ago
7 0

Answer:  Carboxylic acid

Explanation:  Bee stings are basically venomous in nature and they do create excruciating pain because they contain Formic acid which belongs to the carboxylic acid group.

Formic acid has a pKa of 3.5 approximately. Thus it is moderately acidic in nature . That is why it is recommended to treat it with some kind of alkali like Baking soda or toothpaste etc.

The structure of the formic acid is displayed in the image attached.

QveST [7]3 years ago
3 0
The Answer is B - <span>carboxylic acid </span>

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The one that will dissolve most quickly is : D. a tablespoon of ultrafine sugar

Unlike any other type of sugar, ultrafine sugar tend to have smaller crystal size. Which means that this substance will dissolve easier if it put into liquid such as tea or water

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3 years ago
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Answer:

160.3 g S

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Why does the hull of an ocean -going ship rust quickly?
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3 years ago
Sometimes in lab we collect the gas formed by a chemical reaction over water (see sketch at right). This makes it easy to isolat
zepelin [54]

Answer:

The correct answer is 0.12 grams.

Explanation:

The mass of carbon monoxide or CO collected in the tube can be determined by using the ideal gas equation, that is, PV = nRT.

Based on the given question, P or the pressure of the gas is given as 1 atm, volume of the gas collected in the tube is 117 ml or 0.117 L.  

The number of moles or n can be determined by using the equation, mass/molar mass.  

R is the universal gas constant, whose value is 0.0821 L atmK^-1mol^-1, and temperature is 55 degree C or 328 K (55+273).  

On putting the values we get:

n = PV/RT

= (1 atm*0.117 L) / (0.0821 L atmK^-1mol^-1 * 328 K)

= 0.0043447 mol

Therefore, mass of CO will be moles * molar mass of CO

= 0.0043447 mol * 28 g/mol

= 0.12 g

3 0
3 years ago
A 25.0-mL sample of 0.150 M hydrazoic acid, HN3, is titrated with a 0.150 M NaOH solution. What is the pH after 13.3 mL of base
tamaranim1 [39]

Answer:

pH ≅ 4.80

Explanation:

Given that:

the volume of HN₃ = 25 mL = 0.025 L

Molarity of HN₃ = 0.150 M

number of moles of HN₃ = 0.025 × 0.150

number of moles of HN₃ =  0.00375  mol

Molarity of NaOH = 0.150 M

the volume of NaOH = 13.3 mL = 0.0133

number of moles of NaOH = 0.0133× 0.150

number of moles of NaOH = 0.001995 mol

The chemical equation for the reaction of this process can be written as:

HN_3 + OH- ---> N^-_{3} + H_2O

1 mole of hydrazoic acid react with 1 mole of hydroxide to give nitride ion and water

thus the new number of moles of HN₃ = 0.00375 - 0.001995 = 0.001755 mol

Total volume used in the reaction =  0.025 +  0.0133 = 0.0383  L

Concentration of HN_3 = \dfrac{0.001755}{0.0383} = 0.0458 M

Concentration of N^{-}_3 = \dfrac{ 0.001995 }{0.0383} = 0.0521 M

GIven that :

Ka = 1.9 x 10^{-5}

Thus; it's pKa = 4.72

pH =4.72 +  log(\dfrac{ \ 0.0521}{0.0458})

pH =4.72 + log(1.1376)

pH =4.72 + 0.05598

pH =4.77598

pH ≅ 4.80

3 0
3 years ago
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