Answer:
a)R= sqrt( wt³/12wt)
b)R=sqrt(tw³/12wt)
c)R= sqrt ( wt³/12xcos45xwt)
Explanation:
Thickness = t
Width = w
Length od diagonal =sqrt (t² +w²)
Area of raectangle = A= tW
Radius of gyration= r= sqrt( I/A)
a)
Moment of inertia in the direction of thickness I = w t³/12
R= sqrt( wt³/12wt)
b)
Moment of inertia in the direction of width I = t w³/12
R=sqrt(tw³/12wt)
c)
Moment of inertia in the direction of diagonal I= (w t³/12)cos 45=( wt³/12)x 1/sqrt (2)
R= sqrt ( wt³/12xcos45xwt)
Answer: hope it helps
Explanation:Moving air has a force that will lift kites and balloons up and down. Air is a mixture ... Here is a simple computer simulation that you can use to explore how wings make lift. ... All these dimensions together combine to control the flight of the plane. A pilot ... When the rudder is turned to one side, the airplane moves left or right.
Answer:
the state of the circuit is a function of the voltage level. The interpretation is up to the user.
Explanation:
A binary digital circuit adopts one of two states, depending on whether the voltage level is above or below some threshold that depends on the design of the circuit. Within each state, the voltage may have some typical range. When the voltage is near the threshold, the state of the circuit may actually be "indeterminate".
The internal/output voltage is a function of the state of the circuit. The interpretation of that voltage as a true/false or 1/0 or other meaning is up to the user of the circuit.
The circuit interprets a given input voltage as intending to convey a particular input signal state according to the circuit specifications. Input voltages near the threshold between states may cause unexpected or even destructive results.
__
In order to conserve space, some digital circuits use more than 2 different voltage levels to signify more than 2 different states.
Answer:
There are 2 expected readings greater than 2.70 V
Solution:
As per the question:
Total no. of readings, n = 60 V
Mean of the voltage, 
standard deviation, 
Now, to find the no. of readings greater than 2.70 V, we find:
The probability of the readings less than 2.70 V, 
:
Now, from the Probability table of standard normal distribution:
Now,
Now, for the expected no. of readings greater than 2.70 V:
No. of readings expected to be greater than 2.70 V = 
No. of readings expected to be greater than 2.70 V = 
≈ 2
