Answer: You need to lift a load of 15 tons (30,000 pounds) a distance of 25 feet. The distance is measured from the center pin of the crane to the center of the load. Once you determine the distance, look on that line for the largest capacity; that will indicate how many feet of boom must be extended
Explanation:
Designing systems for manufacturing, motion analysis or impact testing;
building and testing prototypes;
analyzing the human body to prevent injury;
developing or designing new light weight materials that will be more comfortable and withstand greater impacts or forces;
Answer:
11.52 hp
Explanation:
<u><em>Givens: </em></u>
p_1 = 15 pisa
p_2 = 70 pisa
V_ol=1.5 ft^3/s
<u><em>Solution: </em></u>
Note: m = p x V_ol (assuming in compressible flow —> p =const)
The total change in the system mechanical energy can be calculated as follows,
Δ
e= (p_2 - p_1 ) /p
The power needed can be calculated as follows
P = W =mΔ
e = p x V_ol x(p_2 - p_1 ) /p
= V_ol x (p_2 - p_1 )
= 44 pisa. ft^3/s
= 44 x (1 btu/5.404pisa. ft^3) x (1 hp/0.7068btu/s)
= 11.52 hp
To develop the problem it is necessary to apply the concepts related to the ideal gas law, mass flow rate and total enthalpy.
The gas ideal law is given as,
Where,
P = Pressure
V = Volume
m = mass
R = Gas Constant
T = Temperature
Our data are given by
Note that the pressure to 38°C is 0.06626 bar
PART A) Using the ideal gas equation to calculate the mass flow,
Therfore the mass flow rate at which water condenses, then
Re-arrange to find
PART B) Enthalpy is given by definition as,
Where,
= Enthalpy of dry air
= Enthalpy of water vapor
Replacing with our values we have that
In the conversion system 1 ton is equal to 210kJ / min
The cooling requeriment in tons of cooling is 437.2.