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ladessa [460]
3 years ago
15

The final position of a car can be predicted with the following equation: Position = -2.5 (time) + 25 Where is the car’s positio

n at 3.0 seconds? When would the car reach position 0.0 meters?
Engineering
1 answer:
nekit [7.7K]3 years ago
8 0

Answer:

The car's position at 3.0 seconds is 17.5 meters. The car will reach 0.0 meters at 10 seconds.

Explanation:

You can rewrite the equation as P= -2.5t+25. t=time and P is equal to position; so you will plug in 3.0 seconds into t. The equation will now look like: P = -2.5(3.0)+25

P = -2.5(3.0) + 25

P = -7.5 + 25

P = 17.5 meters

Now, to find when the car reaches 0.0 meters, we will plug that into P since P = position and will solve for t.

P = -2.5t + 25

0.0 = -2.5t + 25

-25                 -25

-25 = -2.5t

-25/-2.5 = -2.5t/-2.5

10 = t

So the car will reach 0.0 meters at 10 seconds.

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Answer:

#include <stdio.h>

typedef struct InventoryTag_struct {

int itemID;

int quantityRemaining;

} InventoryTag;

int main(void) {

InventoryTag redSweater;

redSweater.itemID = 314;

redSweater.quantityRemaining = 500;

/* Your solution goes here */

printf("Inventory ID: %d, Qty: %d\n",redSweater.itemID,redSweater.quantityRemaining);

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return 0;

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Explanation:

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3 years ago
A insulated vessel s has two compartments separated by a membreane. On one side is 1kg of steam at 400 degC and 200 bar. The oth
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Answer:

See explaination

Explanation:

See attachment for the detailed step by step solution of the given problem.

5 0
2 years ago
Determine the speed of sound in air at 400 K. Also determine the Mach number of an aircraft moving in the air at a velocity of 3
Reika [66]

Answer:

\alpha = \sqrt{1.4 *0.287 \frac{KJ}{Kg K}*\frac{1000J}{1KJ} *400 K}= 400.899 m/s

Ma= \frac{310 m/s}{400.899 m/s}= 0.773

Explanation:

For this case we have given the following data:

T= 400 K represent the temperature for the air

v = 310 m/s represent the velocity of the air

k = 1.4 represent the specific heat ratio at the room

R = 0.287 KJ/ Kg K represent the gas constant  for the air

And we want to find the velocity of the air under these conditions.

We can calculate the spped of the sound with the Newton-Laplace Equation given by this equation:

\alpha = \sqrt{\frac{K}{\rho}}=\sqrt{k RT}

Where K = is the Bulk Modulus of air, k is the adiabatic index of air= 1.4, R = the gas constant  for the air, \rho the density of the air and T the temperature in K

So on this case we can replace and we got:

\alpha = \sqrt{1.4 *0.287 \frac{KJ}{Kg K}*\frac{1000J}{1KJ} *400 K}= 400.899 m/s

The Mach number by definition is "a dimensionless quantity representing the ratio of flow velocity past a boundary to the local speed of sound" and is defined as:

Ma=\frac{v}{\alpha}

Where v is the flow velocity and \alpha the volocity of the sound in the medium and if we replace we got:

Ma= \frac{310 m/s}{400.899 m/s}= 0.773

And since the Ma<0.8 we can classify the regime as subsonic.

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Explanation:

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A chatter group can be used to share ideas both privately and publicly. These groups can have more than 30,000 people or just 3 people, it depends on how many are interested in the topic or product. The groups can be made unlisted and by invite only and then you can see with whom you are talking to. Nonmembers can view anything written in the public and archived groups. This is a great way to see how your peers are doing with their product.

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