Answer:
i) for NaOH (or KOH) = 13.75 mL
ii) for = 13.50 mL.
Explanation:
Phenolphthalein is an indicator which shows change in color when the conditions are highly basic.
Methyl orange is an indicator which shows change in color in presence of highly acidic medium.
For titration of NaOH and HCl we can use phenolphthalein but for sodium carbonate (a weak base) with HCl we use mehtyl orange.
Now in case of mixture of given strong base and weak base the reading or end point obtained from phenolphthalein, shows the neutralization of NaOH only and half neutralization of sodium carbonate.
While the reading or end point of methyl orange shows the neutralization of both the base present.
a) The volume of HCl used for phenolphthalein end point = 20.50 mL
Let us say the volume of HCl used for NaOH = V1
The volume of HCl used for half neutralization of sodium carbonate = V2
(1)
b) the volume of HCl used for methyl organe end point = 27.25
This volume of HCl used for both NaOH and Na₂CO₃
(2)
Equating equation 1 and 2
i) Thus the volume of Acid used for NaOH (Or KOH if present in place of NaOH) = 20.50-6.75= 13.75 mL
ii) the volume of acid used for sodium carbonate =
Answer:
1) open system is the system through which both matter and energy and enter as well as leave
ex - open beaker
2) close system is the system through which only energy can leave but matter cannot
ex - pressure cooker.. ( energy leave as air)
3) Valency of an atom is the no. of outer most electron which can participate in a reaction.
4). Heisenberg uncertainty principal states that it is impossible to measure or calculate exactly, both the position and the momentum of an object
5) The reaction in which heat is required to make products are called endothermic reaction. it cools down the surrounding .
The best way to know would be knowing what the electronic configuration of the element is. The electronic configuration of sulfur is 1s2 2p2 2p6 3s2 3p4. The p subshell can house a maximum of 6 electrons, but at this time it clutches 4 electrons, which means that sulfur has 2 unpaired electrons, both placed in the p-subshell. Or it could also be seen easily in the Lewis Dot Structure of Sulfur, you can see that there are two that has no pairs.
Answer:
C I think from what I did to solve!!
Answer:
3.4 × 10^23 molecules
Explanation:
To find the number of molecules present in C6H14, we multiply the number of moles in the compound by Avagadro's number (6.02 × 10^23 atoms).
number of molecules = number of moles (mol) × 6.02 × 10^23?
Number of molecules = 0.565 × 6.02 × 10^23
3.4 × 10^23 molecules