Can a centigram balance be read to the nearest milligram?
2 answers:
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Answer:
a: before equivalence point
b: equivalence point
c: before equivalence point
d: after the eqivalence point
e: before equivalence point
f: after the eqivalence point
Explanation:
Balanced equation of reaction:
NaOH +HCl =NaCl +H2O;
Volume of HCl is fixed and it 100ml and concentration is 1.0M
N1 and N2 normality of HCl and NaOH respectively;
V1 and V2 volume of HCl and NaOH respectively;
we have given molarity but we need normality;
<em>but in case of NaOH and HCl n-factor is 1 for each.</em>
hence
normality=molarity;
At equivalence point:
Before equivalence point :
After the equivalence point:
case a: 5.00 mL of 1.00 M NaOH
hence it is before equivalence point
case b: 100mL of 1.00 M NaOH
hence it is equivalence point
case c: 10.0 mL of 1.00 M NaOH
hence it is before equivalence point
case d: 150 mL of 1.00 M NaOH
hence it is after the eqivalence point
case e: 50.0 mL of 1.00 M NaOH
hence it is before equivalence point
case f: 200 mL of 1.00 M NaOH
hence it is after the eqivalence point
1) D = 13.6 g / mL
2)ethyl alcohol weighs 158g
3)ρ
_copper = 8.9 g
Explanation:
1)
D = m / V
=306.0 g / 22.5 mL
D= 13.6 g / mL
2)
density = mass / volume
mass = density × volume
=0.789g /ml × 200.0 ml
M=158g
Ethyl alcohol weighs 158g
3)
ρ (density) = Mass / Volume
ρ _copper = 1896 g / 8.4cm × 5.5cm × 4.6cm
= 1896g / 212.5
ρ
_copper=8.9 g