The correct answer is 3) 2CO2(g) ⇄ 2CO(g) + O2(g)
this is the correct one because it is a decomposition reaction and all the number of atoms is equal on both sides.
there are 2 C atoms on both sides.
and 4 O atoms on both sides.
and 1) the atoms numbers are equal on both sides but not correct as it not a
correct number as it has 1/2 O2.
and 2) CO2(g) ⇆ CO(g) + O2
the number of O atoms is not equal on both sides of the equation.
we have 2 O atoms on the left side and 3 O atoms on the right side.
so, this not a balanced equation.
4) also not correct 2CO(g) + O2 ⇆ 2CO2
as it is not a decomposition reaction and the 2CO & O2 are as reactants not products.
so the correct answer is 3) 2CO2(g) ⇆ 2CO(g) + O2(g)
The sample having solid substance is considered as titanium.
<h3>Which sample was titanium?</h3>
That sample is considered as Titanium which is still present as a solid substance because all the other samples turns into liquid state due to high temperature.
While on the other hand, the sample which contains titanium has a solid particles and still solid on high temperature so we can conclude that the sample having solid substance is considered as titanium.
Learn more about titanium here: brainly.com/question/11496905
The most accurate measurement is 1.1 g. Option A
<h3>What is accuracy?</h3>
The term accuracy refers to the fact that the measurement is close to the true value. The closer the measurement is to the true value as given, the more accurate it is.
In this case, the true value of the mass of the sample of calcium carbonate is 1.134 g. Now we have to look at all the masses of as obtained by Emma during the experiment.
The most accurate measurement is 1.1 g. Option A
Learn more about accuracy:brainly.com/question/15276983
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I know it would be calcium chloride, not sure why. Maybe someone could answer that part.
Answer:He 1+
Explanation:
Both Hydrogen atom and helium ion are one electron species. Hence we expect the spectrum of the helium ion to closely resemble that of hydrogen atom also containing one valence electron.
