<span>Kc = [H2S]²*[O2]³ / [H2O]²*[SO2]²
Let x be the moles of H2S formed. Each mole of H2S takes one each mole of H2O and SO2 so after the reactions
[H2O] = 2.8 - x and [SO2] = 2.6 - x also for each mole of H2S, 1.5 moles of O2 are formed, so [O2] = 1.5*x
Kc = x²*(1.5*x)³ / (2.8 - x)²*(2.6 - x)²
Thus use 2.8 - x = 2.8 and 2.6 - x = 2.6 in the above equation for Kc:
Kc = x²*(1.5*x)³ / 2.8²*2.6² = 3.375x^5 / 2.8²*2.6² = 0.06368*x^5
x^5 = 1.3*10^-6 / 0.06368 = 2.0414*10^-5
x = 0.115M </span>
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Answer:
if it has equal positive and negative then neutral. but if there are more electrons than protons then it becomes negative.
Explanation:
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1 gold(lll), 3 fluorine
This is because of the good has a 3+ charge and the fluorine has a 1- charge so they have to balance each other out
Answer:
The percent yield of a reaction is 85.04%
Explanation:

Mass of
= 47.5g
Molar mass of
= 232 g/mole
Molar mass of
= 18 g/mole
Volume of water obtained from the reaction , V= 9.40mL
Mass of water = m = Experimental yield of water
Density of water = d = 1.00 g/mL

Moles of tungsten(VI) oxide =
According to recation 1 mole of tungsten(VI) oxide gives 3 moles of water, then 0.2047 moles of tungsten(VI) oxide will give:

Mass of 0.6141 moles of water:
0.6141 mol × 18 g/mol = 11.054 g
To calculate the percentage yield of reaction , we use the equation:
% yield = {

The percent yield of a reaction is 85.04%