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USPshnik [31]
3 years ago
6

What is an atomic mass unit?​

Chemistry
2 answers:
photoshop1234 [79]3 years ago
8 0

Answer:

a unit of mass used to express atomic and molecular weights, equal to one-twelfth of the mass of an atom of carbon-12. It is equal to approximately 1.66 x 10-27 kg.

Explanation:

hope it helps, mark brainliest please

rjkz [21]3 years ago
3 0

Answer:

A unit of mass used to express atomic and molecular weights, equal to one-twelfth of the mass of an atom of carbon-12. It is equal to approximately 1.66 x 10-27 kg.

Explanation:

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The skeletal structure in line-angle (line-bond) mode of 2,3,3,5-tetramethylhexane is shown. Identify the number of hydrogen ato
Kruka [31]

Answer:

There are 22 hydrogen in 2,3,3,5-tetramethylhexane (C10H22)

From the left to the right of the skeletal structure:

1st Main Carbon = 3 hydrogen

2nd Main Carbon = 1 hydrogen

1st Branch Carbon = 3 hydrogen

3rd Main Carbon = 2 hydrogen

2nd Branch Carbon = 3 hydrogen

3rd Branch Carbon = 3 hydrogen

4th Main Carbon = 0 hydrogen

4th Branch Carbon = 3 hydrogen

5th Main Carbon = 1 hydrogen

6th Main Carbon = 3 hydrogen

Total = 22 hydrogen

Explanation:

This is the skeletal formula for 2,3,3,5-tetramethylhexane - the 2D chemical structure. It is an organic compound. The carbon atoms in the structure are known as the carbon backbone. The hydrogen atoms are linked to the carbon backbone. This provides each carbon atom with four bonds.

6 0
3 years ago
Reaction of tert−butyl pentyl ether [CH3CH2CH2CH2CH2OC(CH3)3] with HBr forms 1−bromopentane (CH3CH2CH2CH2CH2Br) and compound H.
EleoNora [17]

Answer:The compound H is is 2-Methyl prop-1-ene and its structure can be found in attachment. The m/z value of 2-Methyl prop-1-ene is 56 which clearly matches with the mas spectrum data. The structure can also be ascertained using the provided IR data. The IR data has absorption stretching frequency in the region of 1650cm⁻¹ which is due to the C=C double bond. The stretching frequency at 3150-3000cm⁻¹ is due to the unsaturated C-H bond. The stretching frequency at 3000-2850cm⁻¹ is due to the saturated C-H bonds. Kindly refer attachment for the mechanism.

Explanation:

The reaction of tert-butyl ether with HBr leads to the formation of 1-bromopentane and tertbutyl alcohol.

The tert butyl alcohol formed undergoes E1 elimnation reaction to give 2-Methyl prop-1-ene.

The mass spectra and IR data available for the compound H completely matches with that of 2-Methyl prop-1-ene hence we can ascertain that the compound H is 2-Methyl prop-1-ene.

The m/Z value of 2-Methyl prop-1-ene  is 56 which is in compete accordance with the provided data for compound H .

The IR data also completely matches with the structure of 2-Methyl prop-1-ene as the following Infrared absorption peaks are provided which matches with that of 2-Methyl prop-1-ene :

The absorption stretching frequency in the region of 1650cm⁻¹ corresponds to the  C=C double bond which is clearly evident in 2-Methyl prop-1-ene.

The stretching frequency at 3150-3000cm⁻¹ corresponds to  unsaturated C-H bond.

The stretching frequency at 3000-2850cm⁻¹ is due to the saturated C-H bonds.

The mechanism of the reaction involves the following steps:

1. The oxygen atom in tert-butyl pentyl ether is protonated by treating it with Hydrogen bromide and Br⁻ is lost from hydrogen bromide.

2. Now since the oxygen atom is protonated it turns into a good leaving group and can leave as tertiary butyl alcohol. The eliminated Br⁻ now  attacks in a SN2 manner from the back side at the primary carbon center which leads to the formation of 1-Bromopentane and tertiary-butyl alcohol

3.The tert-butyl alcohol formed further reacts with HBr present to give elimiantion product 2-Methyl prop-1-ene  through E1 elimination mechanism. The OH is protonated  and further it gets eliminated  as H₂O leading to formation of  a tertiary carbocation. The tertiary carbocation formed gives an elimination product of 2-Methyl prop-1-ene .

Kindly refer the attachment for complete reaction mechanism.

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