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Lynna [10]
4 years ago
8

Why are solids good at transferring heat through conduction?

Physics
2 answers:
valentinak56 [21]4 years ago
8 0
Not all solids are good at conducting, like plastic or Styrofoam. This question is a little too broad, since there are many different cases that would serve for many different answers.
seraphim [82]4 years ago
6 0
The chemical bonds alow it to pass to the other object.
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An ideal monatomic gas at a pressure of 2.0×105N/m2 and a temperature of 300 K undergoes a quasi-static isobaric expansion from
liraira [26]

Answer:

a) W= 400 J

b) T_{2}=600 K

c) n=0.16 mol

d) \Delta E_{int}=598 J

e) Q=998 J

Explanation:

a) Let's recall the definition of work.

W=\int^{Vf}_{V0}PdV

Because the system is a quasi-static isobaric expansion, P is constant here, therefore:

W=P\int^{Vf}_{V0}dV=P(V_{f}-V_{0})

W=2.0\cdot 10^{5}(4.0\cdot 10^{-3}-2.0\cdot 10^{-3})= 400 [Nm^{2}]

b) Using the ideal gas equation we have:

\frac{P_{1}V_{1}}{T_{1}}=nR (1)

and \frac{P_{2}V_{2}}{T_{2}}=nR (2)

We can note that n times R is a constant in (1) and (2), so we can equal those equations.

\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}} (3)

Let's solve T₂ for (3), let's recall that P₁ = P₂, so they canceled out

T_{2}=T_{1}\cdot V_{2}/V_{1}

T_{2}=300\cdot 4x10^{3}/2x10^{3}=600 K

c) Using the equation of ideal gas we have:

\frac{P_{1}V_{1}}{RT_{1}}=n

n=\frac{P_{1}V_{1}}{RT_{1}}=0.16 mol

d) We can write the internal energy as a function of Cv, and as we know the Cv is 1.5R for a monoatomic gas.

\Delta E_{int}=n1.5R\Delta T

\Delta E_{int}=0.16\cdot 1.5\cdot 8.3 \cdot (600-300)

\Delta E_{int}=598 J

e) Using the first law of thermodynamic, we have:

\Delta E_{int}=Q-W

Finally,

Q=\Delta E_{int}+W=598+400=998 J

Have a nice day!

3 0
3 years ago
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