Answer:
- quality factor (Q) = 69.99
- inductor = 1.591 x 10⁻⁴ H
- capacitor = 3.248 x 10⁻¹⁰ F 
Explanation:
Given;
resonance frequency (F₀) = 700 kHz
resistor, R =  10 Ohm
bandwidth (BW) = 10 kHz
bandwidth (BW)  

make L (inductor) the subject of the formula


make C (capacitor)  the subject of the formula

quality factor (Q) 
quality factor (Q) =  69.99
  
        
             
        
        
        
Answer:
The object's velocity would increase due to the change in force.
Explanation:
 
        
             
        
        
        
Answer:
π/10 rads
Explanation:
It takes an hour (60 minutes) for the minute's hand to turn a full circle or achieve an angular rotation of 
2πl rad. 
Now, number of periods of 3 minutes in an hour is;
Number of periods = 60/3 = 20 periods
Thus, 3 minutes rotation accounts for 1/20 of 2π the rotation of the minute's hand in an hour.
Thus;
Angular displacement = (1/20) * 2π = π/10 rads
 
        
             
        
        
        
Answer:
(a) Initial volume will be 7.62 L 
(b) Final temperature will be 303.85 K
Explanation:
We have given one mole of ideal gas done 3000 J 
So work done W = 3000 J
Let initial volume is  and initial pressure
 and initial pressure  ( As pressure is constant )
 ( As pressure is constant )
Final volume  = 0.025
 = 0.025 
Number of moles n = 1
(B) From ideal gas of equation we know that 
So 
T = 303.85 Kelvin 
(B) For isothermal process work done is equal to 





So initial volume will be 7.62 L