Let s = rate of rotation
<span>Let r = radius of earth = 6,400km </span>
<span>Then solving (s^2) r = g will give the desired rate, from which length of day is inferred. </span>
<span>People would not be thrown off. They would simply move eastward in a straight line while the curved surface of earth fell away from beneath them.</span>
Two teams of five trying to shoot in the hoop, the ball is moving around the court by players drippling or passing, the team with the basketball is called offense
Answer:
a) Δx = t 0.05 + 0.5
, Δx = 0.5 cm, b) Do not present any problem
Explanation:
The kinematic equation for constant speed is
v = x / t
x = v t
a) the uncertainty can be calculated with
Δx = dx /dv Δv + dx /dt Δt
Δx = t Δv + v Δt
Speed is
v = (50.00 ± 0.05) cm / s
The most common uncertainty for the time of Δt = 0.01 s
We replace
Δx = t 0.05 + 50 0.01
Δx = t 0.05 + 0.5
We must know the time to have an explicit value, if we assume that the measure was t = 1s
Δx = 0.5 cm
b)
Do not present any problem since its value is not very small, we must take as soon as the quantum effects and the velocity are not so high that we must take into account the relativistic effects
Answer:
maximum possible temperature is 34.088°C
Explanation:
Given data
power output Q = 37 kW
volume flow rate = 11 x 10^-5 m3/s
temperature t = 14°C
to find out
maximum possible temperature T
solution
we can say
total water volume = 4 residents × volume flow
total water volume = 4 × 11 x 10^-5 = 44 × 10^-5 m³/s
so we say total water mass = 1000 × volume
total water mass = 1000 kg/m³ × 44 × 10^-5
total water mass = 0.44 kg
we know
dQ/dt = (dm/dt)× (S)× ( T - t)
so here we know specific heat of water S = 4.186 joule/gram °C
37 = 0.44 × 4.186 × (T-14)
T = 34.088°C
maximum possible temperature is 34.088°C
Answer:
<em>Asha traveled a distance of 50 m</em>
<em>The displacement is 20 m north.</em>
Explanation:
<u>Distance and Displacement
</u>
A moving object constantly travels for some distances at defined periods of time. The total moved distance is the sum of each individual distance the object traveled. It can be written as:
dtotal=d1+d2+d3+...+dn
This sum is obtained independently of the direction the object moves.
The displacement only takes into consideration the initial and final positions of the object while moving. The displacement, unlike distance, is a vectorial magnitude and can even have magnitude zero if the object starts and ends the movement at the same point.
Asha walks 15 m west, 20 m north, and 15 m east. The total distance is
dt=15 m + 20 m + 15 m = 50 m
Asha traveled a distance of 50 m
Note the final position is 20 m above the initial position since she goes 15 m west and 15 m east. Thus the displacement is 20 m north.
