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Sedaia [141]
3 years ago
10

Hi i have homework can you help me

Physics
1 answer:
soldier1979 [14.2K]3 years ago
6 0

Explanation:

The particle will be at rest when its velocity v(t) is equal to zero. Recall that the velocity is simply the derivative of the position x(t) with respect to time:

v(t) = \dfrac{dx}{dt}

Since x(t) = t^2 - 2t + 2

then

v(t) = \dfrac{d}{dt}(t^2 - 2t + 2) = 2t - 2 = 0

Solving for t, we find that the particle will be at rest at

t = 1\:\text{s}

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Answer:

Explanation:

given,

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             v = \sqrt{20^2- 2\times 9.8 \times 5 cos 22^0 }

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b) considering the friction

  \dfrac{1}{2}mv^2 = \dfrac{1}{2}mu^2 - mgh-\mu_kmgl

             v^2 = u^2 - 2gh-2\mu_kmgl

             v = \sqrt{u^2- 2 g h cos 22^0-2\mu_kgl}

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                   v = 17.16 m/s

7 0
3 years ago
What are two ways in which all types of precipitation are alike
Digiron [165]
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A cement truck of mass 14,000 kg moving 10m/s slams into a wall and comes to a halt in .2s. What is the force of impact on the t
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Which process is represented by the PV diagram shown below?
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Answer: B. the isovolumetric process

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In the graph given, the volume is constant throughout. It represents a constant volume process. Such processes are called the isovolumetric process or isochoric process.

<em>Hence, option B is the correct answer.</em>

Option A is incorrect because in an isobaric process, the pressure is constant.

Option C is incorrect because in an isothermal process, the temperature is constant.

Option D is incorrect because in an adiabatic process there is no heat transfer.

8 0
3 years ago
"Giant Swing", the seat is connected to two cables as shown in the figure (Figure 1) , one of which is horizontal. The seat swin
Bingel [31]
The horizontal force is m*v²/Lh, where m is the total mass. The vertical force is the total weight (233 + 840)N. 

<span>Fx = [(233 + 840)/g]*v²/7.5 </span>

<span>v = 32.3*2*π*7.5/60 m/s = 25.37 m/s </span>

<span>The horizontal component of force from the cables is Th + Ti*sin40º and the vertical component of force from the cable is Ta*cos40º </span>

<span>Thh horizontal and vertical forces must balance each other. First the vertical components: </span>

<span>233 + 840 = Ti*cos40º </span>

<span>solve for Ti. (This is the answer to the part b) </span>

<span>Horizontally </span>

<span>[(233 + 840)/g]*v²/7.5 = Th + Ti*sin40º </span>

<span>Solve for Th </span>

<span>Th = [(233 + 840)/g]*v²/7.5 - Ti*sin40º </span>

<span>using v and Ti computed above.</span>
3 0
3 years ago
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