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Lunna [17]
3 years ago
10

What is the molarity of a 5.0 L solution that contains 0.5 moles of KNO3

Chemistry
1 answer:
pashok25 [27]3 years ago
8 0

Answer:

Molarity of a 5.0 L solution that contains 0.5 moles of KNO3 is 0.1 M

Explanation:

Molarity : It is used to express the concentration of the solution and defined as total moles of solute present in one liter of solution .

Molarity =\frac{moles\ of\ solute}{volume\ of\ solution(L)}

Moles of KNO3 = 0.5 (given)

Volume of solution = 5.0 L

Substitute the value in given formula ,

Molarity =\frac{0.5\ moles }{5.0\ L}

on calculation,

Molarity = 0.1 mol/L

Molarity = 0.1 M

(M = mol/L)

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Which of the following is true of group 6A?
USPshnik [31]

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The answer to your question is: Includes sulfur and gain two electrons

Explanation:

Includes Chlorine  This option is wrong, Chlorine belongs to group VII.

Includes Sulfur  This option is true, Group VI includes Oxygen, Sulfur, Selenium, Tellurium.

Gain 2 electrons . This option is true, Elements in group VI have six valence electrons so they gain to electrons to become estable.

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7 0
3 years ago
The density of an aqueous solution of nitric acid is 1.64 g/mL and the concentration is 1.85 M. What is the concentration of thi
galina1969 [7]

Answer:

Mass % of the solution = 7.1067 %

Explanation:

Given :

Molarity of nitric acid solution = 1.85 M

Density of the solution = 1.64 g/mL

<u>Molarity of a solution is defined as the number of moles of solute present in 1 liter of the solution.</u>

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Lets, consider the volume of the solution = 1 L

Thus,

Moles of nitric acid present in the solution:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Moles of Nitric acid=Molarity \times {Volume\ of\ the\ solution}

So,

Moles of Nitric acid  = 1.85 moles

Molar mass of nitric acid = 63 g/mol

The mass of Nitric acid can be find out by using mole formula as:

moles=\frac{Mass\ taken}{Molar\ mass}

Thus,  

Mass\ of\ Nitric\ acid=Moles \times Molar mass}

Mass\ of\ Nitric\ acid=1.85 g \times 63 g/mol}

<u>Mass of Nitric acid = 116.55 g</u>

Also,

Density=\frac{Mass}{Volume}

Given : Density = 1.64 g/mL

Also, 1 L = 10³ mL

Volume of the solution is 1000 mL

So, mass of the solution:

Mass\ of\ the\ solution=Density \times {Volume\ of\ the\ solution}

Mass\ of\ the\ solution=1.64 g/mL \times {1000 mL}

<u>Mass of the solution  = 1640 g</u>

Mass % is defined as the mass of solute in 100 g of the solution. The formula for the calculation of mass % is shown below:

Mass \% =\frac{Mass\ of\ the\ solute}{Mass\ of\ the\ solution} \times {100}

So,

Mass \%=\frac{116.55}{1640} \times {100}

<u>Mass % = 7.1067 %</u>

6 0
3 years ago
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