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3 years ago

Emission of light from an atom occurs when an electron

Physics

2 answers:

il63 [147K]3 years ago

8 0

When, it goes for lower orbital

OverLord2011 [107]3 years ago

3 0

When an electron goes to lower orbital from higher orbital.

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A vector is<br> In English

zzz [600]

A vector is a quantity or phenomenon that has two independent properties: magnitude and direction.

3 0

3 years ago

suppose you press a basketball against a wall. what happpens to the basketball when you are pressing it?

AURORKA [14]

It hardens because you are pressing it against something.

5 0

3 years ago

if a Firebird travels at a velocity of 0 to 60 mph in four seconds traveling east what was the acceleration of the Firebird

Tresset [83]

Answer:

6.7 m/s^2

Explanation:

The formula of acceleration is:

$\displaystyle{\vec{a} = \dfrac{\Delta \vec{v}}{\Delta t} = \dfrac{v_2 - v_1}{t_2-t_1}}$

where $\displaystyle{\vec{a}}$ is acceleration, $\displaystyle{\vec{v}}$ is velocity and $\displaystyle{t}$ is time. $\displaystyle{v_2}$ means final velocity. $\displaystyle{v_1}$ means initial velocity, $\displaystyle{t_2}$ means final time and $\displaystyle{t_1}$ means initial time.

We are given that the Firebird travels at velocity of 0 to 60 mph in four seconds. Therefore:

Our initial velocity starts at 0 mph.
Our final velocity is at 60 mph.
Our initial time is 0 second.
Our final time is 4 seconds.

Since it travels to the east then our vector will be positive. However, acceleration has to be in m/s^2 unit (Sl unit) so we'll have to convert from mph (miles per hours) to m/s (meters per second) first.

We know that:

A mile equals to 1609.344 meters.
An hour equals to 60 minutes which a minute equals to 60 seconds. So 60 minutes will equal to 3600 seconds.

Now we divide 1609.344 by 3600 to find a unit rate of m/s:

$\displaystyle{\dfrac{1609.344}{3600} \ \, \sf{m/s}}\\\\\displaystyle{= 0.44704 \ \, \sf{m/s}}$

Now multiply 0.44704 m/s by 0 and 60 to get velocity in m/s unit:

Initial velocity = 0 m/s
Final velocity = 60 * 0.44704 = 26.82 m/s

Time is already in second so no need for conversion. Substitute known information in the formula:

$\displaystyle{\vec{a} = \dfrac{26.82-0}{4-0}}\\\\\displaystyle{\vec{a} = \dfrac{26.82}{4}}\\\\\displaystyle{\vec{a} = 6.7 \ \, \sf{m/s^2}}$

Therefore, the Firebird will accelerate at the rate of 6.7 m/s^2.

3 0

2 years ago

A straight 2.20 m wire carries a typical household current of 1.50 A (in one direction) at a location where the earth's magnetic

Y_Kistochka [10]

A) Upward

In order to find the direction of the magnetic force on the wire, we can use the right-hand rule: the index finger, the middle finger and the thumb of the right hand must be placed all of them perpendicular to each other.

So we have:

- Index finger: direction of current in the wire (from west to east)

- Middle finger: direction of magnetic field (from south to north)

- Thumb: direction of the force --> so it will be upward

So, the force will point upward.

B) $1.82\cdot 10^{-4}N$