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Alekssandra [29.7K]
4 years ago
9

Which character trait below is a trait that both Michael Faraday and Nikola Tesla had?

Physics
1 answer:
-Dominant- [34]4 years ago
7 0
They were both odd and obsessive
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I need help with my physics homework agh! Please help it's due tomorrow. <br>​
storchak [24]

Rubbing both pieces cause each piece to have a negative charge.

When two parts have the same they repel each other, so holding one piece up tot he end of the other piece would push it away.

Because one piece is held in the middle by a string, it would rotate the piece in a circle.

If they held the piece to the other end of the one held by a string it would start to rotate in the opposite direction.

4 0
3 years ago
A football player kicks a ball horizontally off a hill with an initial velocity of 42.0 m/s. It travels a horizontal distance of
damaskus [11]

Explanation:

.........................

7 0
4 years ago
What is a Non-Example of Newton's 1st law?
guajiro [1.7K]

Answer:

Say a 14 year old girl was at a construction site and she was asked to move something like a 10,000 pound brick( one brick). She would be acting on it as the unbalanced force but they would still not change their position.

so to say the girl would be doing everything she could to move that brick but the brick would still be in that same spot so the unbalanced force (the girl) would be acting on the thing that was at rest but it wouldn't move.

so the unbalanced force would not really be acting on the thing at rest; even though the unbalanced force was doing something to the brick.

( just think about it and you will eventually get it...just imagine in your head...)

Explanation:

5 0
3 years ago
Autotrophic plants do not require which of the following? solar energy carbon dioxide water oxygen NextReset
alukav5142 [94]
<span>Autotrophic plants do not require "Oxygen" as it is a waste product of the process of photosynthesis which they do.

In short, Your Final Answer would be Option D

Hope this helps!</span>
4 0
4 years ago
A large box slides across a frictionless surface with a velocity of 12 m/s and a mass of 4
denpristay [2]
Answer= 8m/s

Because total Momentum before= total momentum after

Momentum before (p=mu)
p=(4)(12)= 48
p=2(0)=0
So total momentum before=48

Momentum after (p=mu)
Masses combined —2+4=6kg
p=6u


Mb=Ma
48=6u
u=8m/s
3 0
3 years ago
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