To convert moles to gram multiply 3.7 moles of BaF2 to the molar mass of BaF2
BaF2 molar mass = 175.326
3.7 moles x 175.326g = 648.70g BaF2
Condensation would occur at that time
Answer:
88.92 grams of Ca(OH)₂ are required
Explanation:
Molarity means mol/L, so 0.6 M are the moles of solute in 1 L of solution.
In 2 L, we 'll have the double of moles, 1.2
Mol . molar mass = grams
1.2 mol . 74.1 g/m = 88.92 grams of solute
Answer:
C.) 3.5 atm
Explanation:
Because you are dealing with pressure and volume, you can use Boyle's Law to help you find the missing variable. The general formula looks like this:
P₁V₁ = P₂V₂
In this formula, "P₁" and "V₁" represent the pressure and volume of the chamber originally. "P₂" and "V₂" represent the final pressure and volume. You have been given the values of all the other variables but "P₂". Therefore, you can plug these values into the formula and simplify to find the final pressure.
P₁ = 1.5 atm
V₁ = 1.4 L
P₂ = ?
V₂ = 0.60 L
P₁V₁ = P₂V₂ <---- Boyle's Law formula
(1.5 atm)(1.4 L) = P₂(0.60 L) <---- Plug in values
2.1 = P₂(0.60 L) <---- Multiply 1.5 and 1.4
3.5 = P₂ <----- Divide both sides by 0.60