Explanation:
they are located in the neucleus
6.7× 10³ g/mol*L ×(1Kg÷1000g) × (1L÷10dL)= 0.67
I think it’s a or d one of those
The moles of disodium edta used is calculated using the below formula
moles =molarity x volume in liters
molarity=0.050m
volume in liters = 22/1000=0.022 L
moles is therefore= 0.022 x0.050 =1.1 x10^-3 moles of disodium edta
The equation representing the decomposition of BaCO₃ is as follow:
BaCO₃(s) ⇄ BaO(s) + CO₂(g)
Standard Gibbs-free energy (ΔG⁰) = 220 kJ/mol
Gas constant (R) = 8.314 x 10⁻³ kJ/K.mol
Temperature (T) =25 + 273 = 298 K
ΔG⁰ = - R T lnK
ln K = - ΔG⁰ / RT = - 88.8
K =
= 2.7 x 10⁻³⁹
So the equilibrium constant of the reaction at 298 K is 2.7 x 10⁻³⁹
From the equation:
Equilibrium constant Kp = Pco₂
= 2.7 x 10⁻³⁹ atm