If the molar mass of calcium hydroxide (Ca(OH)2) is 74.1 g/mol, how many grams of calcium hydroxide are required to prepare 2.00
liters of 0.60 M calcium hydroxide
1 answer:
Answer:
88.92 grams of Ca(OH)₂ are required
Explanation:
Molarity means mol/L, so 0.6 M are the moles of solute in 1 L of solution.
In 2 L, we 'll have the double of moles, 1.2
Mol . molar mass = grams
1.2 mol . 74.1 g/m = 88.92 grams of solute
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