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Lelu [443]
2 years ago
15

What is the number of atoms per unit cell for each metal? (b) Manganese, Mn

Chemistry
1 answer:
Veseljchak [2.6K]2 years ago
6 0

The amount of atoms per unit cell needed to answer the question is:

Manganese (Mn)

With 8 corner atoms and 1 central atom, the Mn structure can be categorized as a body-centered cubic (BCC), with a total of 2 bits per unit cell.

With the atomic number 25 and the symbol Mn, manganese is a chemical element. It is a complicated, fragile, silvery metal that is frequently found alongside iron in minerals. Stainless steel, in particular, uses manganese, a transition metal with a wide range of industrial alloy applications. Strength, workability, and wear resistance all improve. In addition to being a rubber additive and an oxidizing agent, manganese oxide is also used to make ceramics, glass, fertilizers, and ceramics.

To learn more about manganese refer here:

brainly.com/question/26448840

#SPJ4

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The dimensions of a cupboard are 1.31 m wide
Mnenie [13.5K]

Answer:

The volume of cupboard is 2.0043 m³.

Explanation:

Given data:

width of cupboard = 1.31 m

length of cupboard = 0.9 m

height of cupboard = 1.70 m

Volume = ?

Solution:

Volume = length × width × height

Volume = 0.9 m × 1.31 m × 1.70 m

Volume = 2.0043 m³

The volume of cupboard is 2.0043 m³.

4 0
3 years ago
Read 2 more answers
Look at the wave in the picture. If it has a wavelength of 2 cm, how far apart are points A and B? How do you know?
Harlamova29_29 [7]

Answer:

picture is not there.....

8 0
3 years ago
Why is sublimation such a critical component for the water cycle in cold climates?
Bumek [7]
The air is so dry that when it hits a snowpack, the frozen water evaporates, going directly from the ice to vapor and bypassing the liquid phase entirely. This is called sublimation, and it's a common way for snow to disappear in the arid West."
5 0
3 years ago
Read 2 more answers
An atom has a diameter of 2.50 Å and the nucleus of that atom has a diameter of 9.00×10−5 Å . Determine the fraction of the volu
chubhunter [2.5K]

Answer:

The fraction of the volume of the atom that is taken up by the nucleus is 4.6656\times 10^{-14}.

The density of a proton is 6.278\times 10^{14} g/cm^3.

Explanation:

Diameter of the atom ,d = 2.50 Å

Radius of the atom ,r = 0.5 d=0.5 × 2.50 Å = 1.25Å

Volume of the sphere= \frac{4}{3}\pi r^3

Volume of atom = V

V=\frac{4}{3}\pi r^3..[1]

Diameter of the nucleus ,d' = 9.00\times 10^{-5}\AA

Radius of the nucleus ,r' = 0.5 d'=0.5\times 9.00\times 10^{-5}\AA=4.5\times 10^{-5}\AA

Volume of nucleus = V'

V=\frac{4}{3}\pi r'^3..[2]

Dividing [2] by [1]

\frac{V'}{V}=\frac{\frac{4}{3}\pi r'^3}{\frac{4}{3}\pi r^3}

=\frac{r'^3}{r^3}=\frac{(4.5\times 10^{-5}\AA)^3}{(1.25 \AA)^3}

\frac{V'}{V}=4.6656\times 10^{-14}

The fraction of the volume of the atom that is taken up by the nucleus is 4.6656\times 10^{-14}.

Diameter of the proton ,d = 1.72\times 10^{-15} m = 1.72\times 10^{-13} cm

1 m = 100 cm

Radius of the proton,r = 0.5 d=0.5\times 1.72\times 10^{-13} cm=8.6\times 10^{-14} cm

Volume of the sphere= \frac{4}{3}\pi r^3

Volume of atom = V

V=\frac{4}{3}\times 3.14\times (8.6\times 10^{-14} cm)^3=2.664\times 10^{-39}cm^3

Mass of proton, m = 1.0073 amu = 1.0073\times 1.66054\times 10^{-24} g

1 amu = 1.66054\times 10^{-24} g

Density of the proton : d

d=\frac{m}{V}=\frac{1.0073\times 1.66054\times 10^{-24} g}{2.664\times 10^{-39}cm^3}=6.278\times 10^{14} g/cm^3

The density of a proton is 6.278\times 10^{14} g/cm^3.

5 0
3 years ago
3. KMnO4<br> name compound
dimaraw [331]

Potassium Peramanganate .

The equation is followed as

\\ \ast\sf\hookrightarrow {K\atop Potassium}+{MnO_4\atop Manganeese\:Oxide}\longrightarrow {KMnO_4\atop Potassium\:Peramanganete}

5 0
3 years ago
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