What is the number of atoms per unit cell for each metal? (b) Manganese, Mn

Chemistry

1 answer:

Veseljchak [2.6K]1 year ago

6 0

The amount of atoms per unit cell needed to answer the question is:

Manganese (Mn)

With 8 corner atoms and 1 central atom, the Mn structure can be categorized as a body-centered cubic (BCC), with a total of 2 bits per unit cell.

With the atomic number 25 and the symbol Mn, manganese is a chemical element. It is a complicated, fragile, silvery metal that is frequently found alongside iron in minerals. Stainless steel, in particular, uses manganese, a transition metal with a wide range of industrial alloy applications. Strength, workability, and wear resistance all improve. In addition to being a rubber additive and an oxidizing agent, manganese oxide is also used to make ceramics, glass, fertilizers, and ceramics.

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How many grams of Co3+ are present in 2.34 grams of cobalt(III) nitrite?

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$m_{Co^{3+}}=0.563gCo^{3+}$

Explanation:

Hello there!

In this case, since these mole-mass relationships are understood in terms of the moles of the atoms forming the considered compound, we first realize that the chemical formula of the cobalt (III) nitrate is Co(NO₃)₃ whereas there is a 1:1 mole ratio of the cobalt (III) ion (molar mass = 58.93 g/mol) to the entire compound. In such a way, we first compute the moles of the salt (molar mass = 58.93 g/mol) and then apply the aforementioned mole ratio to obtain the grams of the required cation:

$m_{Co^{3+}}=2.34gCo(NO_3)_3*\frac{1molCo(NO_3)_3}{244.95 gCo(NO_3)_3} *\frac{1molCo^{3+}}{1molCo(NO_3)_3} *\frac{58.93gCo^{3+}}{1molCo^{3+}} \\\\m_{Co^{3+}}=0.563gCo^{3+}$