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Lelu [443]
1 year ago
15

What is the number of atoms per unit cell for each metal? (b) Manganese, Mn

Chemistry
1 answer:
Veseljchak [2.6K]1 year ago
6 0

The amount of atoms per unit cell needed to answer the question is:

Manganese (Mn)

With 8 corner atoms and 1 central atom, the Mn structure can be categorized as a body-centered cubic (BCC), with a total of 2 bits per unit cell.

With the atomic number 25 and the symbol Mn, manganese is a chemical element. It is a complicated, fragile, silvery metal that is frequently found alongside iron in minerals. Stainless steel, in particular, uses manganese, a transition metal with a wide range of industrial alloy applications. Strength, workability, and wear resistance all improve. In addition to being a rubber additive and an oxidizing agent, manganese oxide is also used to make ceramics, glass, fertilizers, and ceramics.

To learn more about manganese refer here:

brainly.com/question/26448840

#SPJ4

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Use the Rydberg equation to find the wavelength (in Å) of the photon absorbed when an electron in an H atom undergoes a transiti
lorasvet [3.4K]

The wavelength of the photon is  1026  Å

Rydberg unit of energy corresponds to the energy of the photon whose wave number is Rydberg constant.

The value for the rydberg constant is 10 973 731.6 m-1

The formula for the rydberg constant for hydrogen is

1 / λ = Rh (1 / n1^2 - 1 / n2^2)

where Rh is the Rydberg constant

For the transition of an electron in a hydrogen atom from n = 1 to n = 3

1 / λ = Rh (1 / 1^2 - 1 / 3^2)

1 / λ = Rh (0.888)

λ = 1.126 / Rh

λ = 1.126 /  10 973 731.6

   = 1.026 * 10^-7

   = 1026  Å

Hence, the wavelength of the photon is  1026  Å

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The volume of 7.91 M HCl needed to make 196.1 mL of 2.13 M HCl is ____.
Alona [7]

Answer:

a. 52.8

Explanation:

To find the number of moles of HCl we use the relation M₁V₁=M₂V₂

where M₁ is the initial molarity, M₂ the new molarity, V₁ the initial volume used, and V₂ the final volume obtained.

M₁=7.91 M

M₂=2.13 M

V₁=?

V₂=196.1 mL

Replacing these values in the relationship.

M₁V₁=M₂V₂

7.91 M× V₁=2.13 M×196.1 mL

V₁=(2.13 M×196.1 mL)/7.91 M

=52.8 mL

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