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ki77a [65]
3 years ago
9

The moon's orbit around the Earth will advance in one day: 1° 13° 27° 29°

Physics
2 answers:
s2008m [1.1K]3 years ago
4 0
13 is the correct answer
Sever21 [200]3 years ago
3 0
<span>The moon's orbit around the Earth will advance in one day:

1°
13° correct answer 
27°
29°</span><span />
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Sally and Susie are astronauts. They went outside the space station to fix something.
rodikova [14]

Answer:

Because sound doesn't move in vacuum (of space)

8 0
3 years ago
Pure sodium metal placed in water will spark and ignite, as well as form bubbles and gas. What are the signs that this is a chem
ad-work [718]
<h3><u>Answer;</u></h3>
  • Heat is produced
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<h3><u>Explanation;</u></h3>
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7 0
3 years ago
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What forces affect a toy car as it moves down a ramp?
Amanda [17]

Answer:

gravity

Explanation:

3 0
2 years ago
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A rocket sled with an initial mass of 3 metric tons, invluding 1 ton of fuel, rests on a level section of track. At t=0, the sol
ELEN [110]

Answer:

v = 719.2 m / s and     a = 83.33 m / s²

Explanation:

This is a rocket propulsion system where the system is made up of the rocket plus the ejected mass, where the final velocity is

           v - v₀ = v_{e} ln (M₀ / M)

where v₀ is the initial velocity, v_{e} the velocity of the gases with respect to the rocket and M₀ and M the initial and final masses of the rocket

In this case, if fuel burns at 75 kg / s, we can calculate the fuel burned for the 10 s

            m_fuel = 75 10

            m_fuel = 750 kg

As the rocket initially had a mass of 3000 kg including 1000 kg of fuel, there are still 250 kg, so the mass of the rocket minus the fuel burned is

              M = 3000 -750 = 2250 kg

let's calculate

            v - 0 = 2500 ln (3000/2250)

            v = 719.2 m / s

To calculate the acceleration, let's use the concept of the rocket thrust, which is the force of the gases on it. In the case of the rocket, it is

             Push = v_{e} dM / dt

let's calculate

             Push = 2500  75

             Push = 187500 N

            If we use Newton's second law

             F = m a

             a = F / m

let's calculate

              a = 187500/2250

              a = 83.33 m / s²

7 0
3 years ago
From the average distance of one of jupiter's moons to jupiter and its orbital period around jupiter, we can determine:
den301095 [7]

Answer: Jupiter's mass

Explanation:

From Kepler's third law:

T^2=\frac{4\pi^2}{GM}a^3

where T is the orbital period of a satellite, a is the average distance of the satellite from the Planet, M is the mass of the planet, G is the gravitational constant.

If the average distance of one of Jupiter's moons to Jupiter and its orbital period around Jupiter is given then mass of the Jupiter can be found:

\Rightarrow M_J=\frac{4\pi^2}{GT_m^2}a_m^3

4 0
3 years ago
Read 2 more answers
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