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andrew-mc [135]
3 years ago
10

What is a short water cycle that takes a short time to complete

Physics
2 answers:
inna [77]3 years ago
7 0
 it will be boiling water be3cause you can warm itg up 
Semenov [28]3 years ago
6 0
This could be like boiling water. it starts in liquid form. Then you boil it, and some evaporates. Then it gathers over time on the pot lid, and in some time you'll have a mini rain shower as it condenses and falls back into the pot.
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In which type of collision is no kinetic energy converted to heat or sound<br> energy?
mezya [45]

Answer:

elastic collision

An elastic collision occurs when the two objects "bounce" apart when they collide. Two rubber balls are a good example. In an elastic collision, both momentum and kinetic energy are conserved. Almost no energy is lost to sound, heat, or deformation.

I hope it's helpful!

5 0
2 years ago
What is one function of a transistor?
const2013 [10]

Answer:

amplifying signals is the correct answer

Explanation:

8 0
2 years ago
The magnitude of the electrical force acting between a +2.4 × 10–8 C charge and a +1.8 × 10–6 C charge that are separated by 0.0
monitta
Use Coulomb law: F = k * q1*q2 / (r^2), where k = 9.00 * 10^9 N.m^2/C^2

F = 9.00 * 10^9 N.m^2/C^2 * 2.4*10^-8 C * 1.8*10^-6 C / [0.008m]^2 = 38.88 * 10^ -5 N

F = 39 * 10 -5N


4 0
3 years ago
Read 2 more answers
Before we can use parallax to measure the distance to a nearby star, we first need to know
Fittoniya [83]
<span>Before we can use parallax to measure the distance to a nearby star, we first need to know the Earth-Sun distance.
Not before we find out what the distance between our planet and the Sun is can we use the parallax to measure the distance to a nearby star.
</span>
6 0
3 years ago
3) An electron moves in a circular orbit of radius 0.11 mm, counterclockwise as you look down at it, moving in a plane above and
andrey2020 [161]

Answer:

B = 0.15 T

Explanation:

To find the magnitude of the magnetic field you use the following formula:

B=\frac{mv}{qr}   ( 1 )

m: mass of the electron = 9.1*10^-31 kg

v: velocity of the electron = 3*10^6 m/s

q: charge = 1.6*10^-19

r: radius = 0.11mm = 0.11*10^-3 m

You replace the values of the parameters in the equation (1).

B=\frac{(9.1*10^{-31}kg)(3*10^6\frac{m}{s})}{(1.6*10^{-19}C)(0.11*10^{-3}m)}=0.15T

the magnetic field has a magnitude of 0.15 T

4 0
3 years ago
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