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UNO [17]
3 years ago
8

A circular loop of wire is held in a uniform magnetic field, with the plane of the loop perpendicular to the field lines. Which

of the following will not cause a current to be induced in the loop?
(a) crushing the loop
(b) rotating the loop about an axis perpendicular to the field lines
(c) keeping the orientation of the loop fixed and moving it along the field lines
(d) pulling the loop out of the field
Physics
1 answer:
frutty [35]3 years ago
4 0

Answer:

(c) keeping the orientation of the loop fixed and moving it along the field lines

Explanation:

Ampere's Law current is calculated by evaluating;

∫ B. dl

Here B= magnetic field and dl- length segment in which current is to flow.

Clearly as magnate field lines are perpendicular to the plane of loop having some length ==> dot product will be zero for 90 ° angle and hence current will be zero in the loop i-e we will keep the position of loop and move it along field lines !

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A baseball hit just above the ground leaves the bat 27 m/s at 45° above the horizontal. A) How far away does the ball strike the
Sedbober [7]

Answer:

A) The ball hits the ground 74.45 m far from the hitting position.

B) Maximum height of the ball = 18.57 m

Explanation:

There are two types of motion in this horizontal and vertical motion.

We have velocity = 27 m/s at 45° above the horizontal

Horizontal velocity = 27cos45 = 19.09 m/s

Vertical velocity = 27sin45 = 19.09 m/s

Time to reach maximum height,

           v = u + at

           0 = 19.09 - 9.81 t

            t = 1.95 s

So total time of flight = 2 x 1.95 = 3.90 s

A) So the ball travels at 19.09 m/s for 3.90 seconds.

     Horizontal distance traveled = 19.09 x 3.90 = 74.45 m

     So the ball hits the ground 74.45 m far from the hitting position.

B) We have vertical displacement

              S = ut + 0.5 at²

              H = 19.09 x 1.95 - 0.5 x 9.81 x 1.95² = 18.57 m

    Maximum height of the ball = 18.57 m

6 0
2 years ago
A transformer has a primary voltage of 115 V and a secondary voltage of 24 V. If the number of turns in the primary is 345, how
Eduardwww [97]
Here's a fun and useful factoid:

               The ratio of the voltages on a transformer is the same
               as the ratio of the number of turns in each winding.

So the ratio of  (345 to the secondary turns)  is  (115V to 24V).

That's a proportion.

                 (115/24)  =  (345/x)

I'll bet you can take it and solve it from here.
Just cross-multiply in the proportion and etc. etc.
6 0
3 years ago
What is reflection of light question mark write the laws of reflection of light ​
Zarrin [17]

Answer:

Reflection of light means the bouncing back of light in another direction after hitting a smooth polished surface

<h3><u>laws </u><u>of </u><u>reflection</u></h3>

1) Angie of incidence is equal to the angle of reflection

2) The nornal ray, reflected ray and the incident ray all lie in the same plane

3 0
2 years ago
Changing the orbit of a spacecraft by firing thrusters is an example of
AleksAgata [21]
Newtons' third Law???
3 0
3 years ago
Measurements made on an operating centrifugal pump indicate that for a flow rate of 240 gpm, 6 HP are being consumed. The operat
Ludmilka [50]

Answer:

62.1 ft

Explanation:

We know that 1 gpm= 0.0022 ft^{3}/s hence 240 gpm will be

240*0.0022=0.528 ft^{3}/s

From the formula of obtaining efficiency

\eta=\frac {\gamma Q h_a}{500W_{in}} and making h_a the subject we have

h_a=\frac {\eta*550*W_{in}}{\gamma Q} where Q is flow rate, \gamma is specific weight of water, h_a is actual head rise and W_{in} is the power input to the compressor

Substituting 0.62 for \eta, 6hp for W_{in}, 62.4 lb/ft^{3} for \gamma and 0.528 ft^{3}/s for Q then

h_a=\frac {0.62*550*6}{62.4*0.528}=\frac {2046}{32.9472}=62.09936\approx 62.1 ft

Therefore, actual head rise of the water being pumped is 62.1 ft

6 0
3 years ago
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