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Darya [45]
3 years ago
7

What is the complete set of quantum numbers for the fifth electron added to a hydrogen ion?

Chemistry
1 answer:
N76 [4]3 years ago
8 0
1s2 2s2 2p1

fifth electron is in 2p orbital 

so answer is  2 2 -1 -1/2 , or 2 2 -1 1/2

*1/2 and -1/2 are spins, so they are interchangeable when writing the first electron in the ml
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The diagram below shows the PH values of several substances.
skelet666 [1.2K]

Answer:

Changes in colour of litmus paper.

  • Blue litmus turns red under acidic conditions.
  • Red litmus turns blue under basic conditions.

Noe

PH values:-

  • K=4
  • M=11

K is acidic as pH is <7

Hence K will change the colour of blue litmus paper.

#B

Examples of substances

  • K=Vinegar, Tomatoes.
  • M=Milk of magnesia,Soap
4 0
2 years ago
If you have 1.005 x 1024 molecules of Ca(OH)2 how many atoms do you have? Moles? Grams?
ira [324]

Answer:

  • 5.025x10²⁴ atoms
  • 1.6686 moles
  • 123.63 g

Explanation:

In one Ca(OH)₂ molecule, there are 5 atoms (1 Ca, 2 O and 2 H). This means that in 1.005x10²⁴ Ca(OH)₂ molecules, there are (5 * 1.005x10²⁴) 5.025x10²⁴ atoms.

To <u>convert molecules into moles</u>, we use <em>Avogadro's number</em>:

  • 1.005x10²⁴ molecules * \frac{1mol}{6.023*10^{23}molecules} = 1.6686 moles

Finally, we <u>convert moles into grams</u> using the <em>molar mass of Ca(OH)₂</em>:

  • 1.6686 moles * 74.093 g/mol = 123.63 g
4 0
3 years ago
40.0 L of oxygen were collected at 10°C and<br> 758 mm of Hg. Calculate its volume at STP.
marta [7]

Answer:

189.5

Explanation:

its very very very very easy

3 0
2 years ago
How many electrons does the isotope oxygen-18 have?<br> 6<br> 8<br> 10<br> 18
Alexxandr [17]
It has 8 electrons I the answer
7 0
3 years ago
The production of NOx gases is an unwanted side reaction of the main engine combustion process that turns octane, C8H18, into CO
borishaifa [10]

Answer:

710,33 g NO2

Explanation:

2 C8H18 + 25 O2 → 16 CO2 + 18 H2O  

(800 g octane) / (114.2293 g C8H18/mol x (25/2)) = 87.54 mol O2 used to combust the octane

87.54 mol O2 x \frac{15}{85} = 15.44 mol O2 used to form NO2

O2 + 2NO → 2NO2

(15.44 mol O2) x (2/2) x (46.0056 g NO2/mol) = 710,33 g NO2

4 0
3 years ago
Read 2 more answers
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