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LenaWriter [7]
3 years ago
7

The diagonals must be congruent in which of the following:

Mathematics
1 answer:
barxatty [35]3 years ago
7 0
Diagonals must be congruent in a rectangle.
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Factor completely 2a^2 + 2b^2 - 5ab
Zinaida [17]

(a - 2b) • (2a - b) is how you factor this using FOIL
5 0
3 years ago
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6x-3=x+7 head d dish’s d dhdndn d zbdndnnd dhdjdd
klasskru [66]

Answer:

0.6

Step-by-step explanation:

6x - 3 = x + 7

6x + 3 = x + 3

6x = x + 10

6x = 10

6 ÷ 10 = 0.6

x = 0.6

5 0
3 years ago
Given: F(x) = 5x - 6 and G(x) = x - 4
fomenos

Answer:

Correct choice is \dfrac{x+26}{5}

Step-by-step explanation:

1. If F(x)=5x-6, then you can find the inverse F^{-1}(x):

y=5x-6,\\ \\5x=y+6,\\ \\x=\dfrac{y+6}{5},\\ \\F^{-1}(x)=\dfrac{x+6}{5}.

2. If G(x)=x-4, then

y=x-4,\\ \\x=y+4,\\ \\G^{-1}(x)=x+4.

3. Hence,

G^{-1}(F^{-1}(x))=G^{-1}\left(\dfrac{x+6}{5}\right)=\dfrac{x+6}{5}+4=\dfrac{x+26}{5}.

7 0
4 years ago
2. The Welcher Adult Intelligence Test Scale is composed of a number of subtests. On one subtest, the raw scores have a mean of
IgorC [24]

Answer:

a) 37.31 b) 42.70 c) 0.57 d) 0.09

Step-by-step explaanation:

We are regarding a normal distribution with a mean of 35 and a standard deviation of 6, i.e., \mu = 35 and \sigma = 6. We know that the probability density function for a normal distribution with a mean of \mu and a standard deviation of \sigma is given by

f(x) = \frac{1}{\sqrt{2\pi}\sigma}\exp[-\frac{(x-\mu)^{2}}{2\sigma^{2}}]

in this case we have

f(x) = \frac{1}{\sqrt{2\pi}6}\exp[-\frac{(x-35)^{2}}{2(6^{2})}]

Let X be the random variable that represents a row score, we find the values we are seeking in the following way

a)  we are looking for a number x_{0} such that

P(X\leq x_{0}) = \int\limits^{x_{0}}_{-\infty} {f(x)} \, dx = 0.65, this number is x_{0}=37.31

you can find this answer using the R statistical programming languange and the instruction qnorm(0.65, mean = 35, sd = 6)

b) we are looking for a number  x_{1} such that

P(X\leq x_{1}) = \int\limits^{x_{1}}_{-\infty} {f(x)} \, dx = 0.9, this number is x_{1}=42.70

you can find this answer using the R statistical programming languange and the instruction qnorm(0.9, mean = 35, sd = 6)

c) we find this probability as

P(28\leq X\leq 38)=\int\limits^{38}_{28} {f(x)} \, dx = 0.57

you can find this answer using the R statistical programming languange and the instruction pnorm(38, mean = 35, sd = 6) -pnorm(28, mean = 35, sd = 6)

d) we find this probability as

P(41\leq X\leq 44)=\int\limits^{44}_{41} {f(x)} \, dx = 0.09

you can find this answer using the R statistical programming languange and the instruction pnorm(44, mean = 35, sd = 6) -pnorm(41, mean = 35, sd = 6)

6 0
4 years ago
Read 2 more answers
What is the answer to the expression “ 13! “
earnstyle [38]

13!=13×12×11×10×9×8×7×6×5×4×3×2×1

=6,227,020,800

5 0
4 years ago
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