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3 years ago

1.0×10−15divided by 4.2×10−7

1 answer:

8 0

1 x 10 - 15 / 4.2 x 10 - 7

Due to order of operations you have to do do the multiplication and division first, from left to right.

So start with 1.0 x 10. This = 10.
Then you have to skip over the subtraction for now. Multiply 15 by 4.2. This equals 63. Then multiply this by 10, so 630.

Then rewrite the equation. It's 10 - 630 - 7. Then just subtract. 10 - 630 = -620.
-620 - 7 = -627. (Two subtracts make an add)

-627 is your answer

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Why do atoms fond bonds

Setler [38]

They bond because they want to make their outer electron shells more stable

Hope this helps

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3 0

3 years ago

At what height above the earth surface will the gravitational acceleration be 5m

slamgirl [31]

Answer: -

The acceleration due to gravity at height r = a = GM/r²

Rearranging

r² = GM /a

= (6.674 x 10⁻¹¹ x 5.972 x 10²⁴ ) / 5

r = 8.917 x 10⁶ m

r = 8917 Km

Now Radius of earth = 6371 Km

So height = 8917 - 6371 = 2546 Km

8 0

3 years ago

How many particles are in 47.7 g of Magnesium? (Round the average

Lynna [10]

Answer:

1.18 × 10²⁴ particles Mg

General Formulas and Concepts:

Chemistry - Atomic Structure

Reading a Periodic Table
Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

Step 1: Define

47.7 g Mg

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of Mg - 24.31 g/mol

Step 3: Convert

$47.7 \ g \ Mg(\frac{1 \ mol \ Mg}{24.31 \ g \ Mg} )(\frac{6.022 \cdot 10^{23} \ particles \ Mg}{1 \ mol \ Mg} )$ = 1.18161 × 10²⁴ particles Mg

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

1.18161 × 10²⁴ particles Mg ≈ 1.18 × 10²⁴ particles Mg

3 0

3 years ago

All of the covalent carbon-carbon bonds in unsaturated hydrocarbons share 2 pairs of electrons.

Evgen [1.6K]

False. carbon-carbon bonds that share 2 pairs of electrons are double bonds. An unsaturated hydrocarbon isnt necessary to only have double bonds. they can also have single bonds or triple bonds.

5 0

3 years ago

Read 2 more answers

NH4CO2NH2(s) equilibrium reaction arrow 2 NH3(g) + CO2(g) Ammonium carbamate decomposes according to the equation above. At 40°C

V125BC [204]

Answer:

Kp = 8.76×10⁻³

Explanation:

We determine the carbamate decomposition in equilibrium:

NH₄CO₂NH₂ (s) ⇄ 2NH₃(g) + CO₂(g)

Let's build the expression for Kp

Kp = (Partial pressure NH₃)² . Partial pressure CO₂

We do not consider, the carbamate because it is solid and we only need the partial pressure from gases

Kp = (0.370atm)² . 0.0640 atm

Kp = 8.76×10⁻³

Remember Kp does not carry units

4 0

3 years ago