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Zina [86]
3 years ago
15

A long homogeneous resistance wire of radius ro = 5 mm is being used to heat the air in a room by the passage of electric curren

t. Heat is generated in the wire uniformly at a rate of g=5'107 W/m as a result of resistance heating. If the temperature of the outer surface of the wire remains at 180°C, determine the temperature at r = 2 mm after steady operation conditions are reached. Take the thermal conductivity of the wire to be k = 8 W/m x °C.
Engineering
1 answer:
VARVARA [1.3K]3 years ago
6 0

Answer:

T = 212.8125°C

Explanation:

Given

radius of the wire, r_{0} = 5 mm 0.005 m

heat generated, g = 5 x 10^{7} W/m^{3}

outer surface temperature, T_{S} = 180°C

Thermal conductivity, k = 8 W / m-k

Now maximum temperature occurs at the center of the wire

that is at r=0,

Therefore, T_{o}=T_{S}+\frac{g\times r_{o}^{2}}{4\times k}

                  T_{o}=180+\frac{5\times 10^{7}\times 0.005^{2}}{4\times 8}

                 T_{o}=219.0625°C

Therefore, temperature at r = 2 mm

\frac{T-T_{S}}{T_{O}-T_{S}}= 1-\left (\frac{r}{r_{O}}  \right )^{2}

\frac{T-180}{219.0625-180}= 1-\left (\frac{2}{5}  \right )^{2}

Therefore, T = 212.8125°C

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Semmy [17]

Answer:

I=9.6×e^{-8}  A

Explanation:

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we have that

(flux)'= -U

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U=4.11×e^{-6}×dI/dt=4.11×e^-6×0.7=2.9×e^-6 (V)

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3 years ago
If welding is being done in the vertical position, the torch should have a travel angle of?
siniylev [52]

Answer:

Between 35°– 45°

Explanation:

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4 0
2 years ago
What is the first test you should do when checking the charging system?
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Answer:

Connect the test light in series with the negative post, and start pulling feed wires. The first to check is the heavy charging wire from the alternator. A bad or leaky diode in an alternator is a very common source of overnight battery drain. Connect wires one at a time to see what lead is drawing current.

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A mixing basin in a sewage filtration plant is stirred by a mechanical agitator with a power input/WF L T=. Other parameters de
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Answer: π= G[√(u.V/W)]

STEP 1

Given parameters:

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STEP 2

We start by expressing the velocity gradient G as a function of W, u, V

G= G(W,u,V)

To get the pii terms, we use the dimension number formula n=k - r

where n and k are natural numbers representing number of fundamental dimensions and variable present respectively.

n= 4-3=1

STEP 3:

We expressed the pii terms as

π= G.W^a.u^b.V^c

The three fundamental F L T

We can write as

Fⁿ.Lⁿ.Tⁿ= 1/T. (FL/T)^a.(FT/L²)^b.(L³)

Using the exponential rule and by comparing coefficient on both sides;

Fⁿ.Lⁿ.Tⁿ= F^a+b. L^a-2b+3c. T^-a+b-1

Fⁿ= F^a+b = a+b= 0..............I

Lⁿ= L^a-2b+3c=0 = a-2b+3c=0...........ii

Tⁿ=L^-a+b-1=0. -a+b-1=0............iii

From the above equations we have,

a+b =0: b=-a...........iv

putting eq. iv into iii , we have

-a-a-1=0: -2a-1=0: a= -1/2

substituting the above value of a into eq iv, we have

b= 1/2

substituting the value of b above into eq 2, we have,

-1/2-2(1/2)+3c=0

c=1/2.

Lastly, from the pii terms given above we can obtain dimensionless relationship,

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We can write this as

π= G[ √1/W.√u. √1/2] = G[(√u.V/√W)] or G[√(u.V/W)].... final answer.

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fiasKO [112]

Answer:

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So the decreasing order of toughness can be given as follows

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